我在DRF中有一个序列化器类,如下所示:
class ProjectSerializer(serializers.HyperlinkedModelSerializer):
created_by = UserSerializer() # created_by is an FK to User model
class Meta:
model = Project
fields = ('id', 'title', 'created_by')
我的看法:
class ProjectList(generics.ListCreateAPIView):
model = Project
serializer_class = ProjectSerializer
filter_fields = ('title',)
def post(self, request, format=None):
serializer = ProjectSerializer(data={
"id": 12,
"title": "FooBar's Project",
"created_by": {
"id": 1,
"username": "foobar",
"first_name": "foo",
"last_name": "bar",
},
})
if serializer.is_valid():
serializer.save()
else:
print serializer.errors
return Response(serializer.data, status=status.HTTP_201_CREATED)
除了DRF抱怨:
{'created_by': [{'username': [u'User with this Username already exists.']}]}
我想要的是参考现有用户创建项目。我在这里做错了什么?
注意:我正在跟踪DRF的主干,而不是来自奶酪店。
最佳答案
如果要分配一个现有用户而不创建一个用户,则嵌套序列化器是不可行的。当您只想向用户添加关系时,您将需要查看关系。PrimaryKeyRelatedField
是可行的方法,由于此字段将是可写的,因此您还需要传递queryset
属性。
created_by = serializers.PrimaryKeyRelatedField(queryset=User.objects.all())
请参阅文档,以检查可以传递给此字段的其他选项:
http://django-rest-framework.org/api-guide/relations#primarykeyrelatedfield
然后您的示例帖子可能如下所示:
def post(self, request, format=None):
user = User.objects.get(pk=8)
serializer = ProjectSerializer(data={
"id": 12,
"title": "FooBar's Project",
"created_by": user.pk,
})