ios - 如何检查NSArray中的对象是否为NSNull？

我得到一个空值的数组。请在下面检查我的数组的结构:

 (
    "< null>"
 )

当我尝试访问索引0时，由于

-[NSNull isEqualToString:]: unrecognized selector sent to instance 0x389cea70

当前，它由于带有崩溃日志的数组而崩溃:

 *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[NSNull isEqualToString:]: unrecognized selector sent to instance 0x389cea70'
*** First throw call stack:
(0x2d9fdf53 0x3820a6af 0x2da018e7 0x2da001d3 0x2d94f598 0x1dee57 0x1dfd31 0x302f598d 0x301a03e3 0x3052aeed 0x3016728b 0x301659d3 0x3019ec41 0x3019e5e7 0x30173a25 0x30172221 0x2d9c918b 0x2d9c865b 0x2d9c6e4f 0x2d931ce7 0x2d931acb 0x3262c283 0x301d3a41 0xabb71 0xabaf8)
libc++abi.dylib: terminating with uncaught exception of type NSException

最佳答案

id object = myArray[0];// similar to [myArray objectAtIndex:0]

if(![object isEqual:[NSNull null]])
{
    //do something if object is not equals to [NSNull null]
}

关于ios - 如何检查NSArray中的对象是否为NSNull？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/19059202/