当我尝试运行程序时,它立即崩溃。问题是我从文件输入的,我可以写到文件中。有人可以解释为什么此代码行不通吗?
StringList::StringList()
{
pTop=NULL;
pBottom=NULL;
ifstream in;
in.open("read.txt");
StringListNode * pCurrent;
pCurrent = new StringListNode;
pCurrent = pTop;
while(!in.eof()) //reads it till the end of file
{
in >> pCurrent->data;
pCurrent = pCurrent->pNext;
}
in.close();
}
此输出到文件工作正常。我以为我会把它包括在内。
StringList::~StringList()
{
ofstream out;
out.open("read.txt");
StringListNode * pCurrent;
pCurrent = new StringListNode;
pCurrent = pTop;
while(pCurrent != 0)
{
out << pCurrent->data << endl;
pCurrent = pCurrent->pNext;
}
out.close();
}
最佳答案
pCurrent = pTop;
为什么在这里分配它?这使pCurrent
为空指针。请删除或修复。
我对您的代码感到困惑:
pCurrent = new StringListNode; // Allocate new memory and point at it
pCurrent = pTop; // Make pCurrent point at same thing as pTop
您两次分配给
pCurrent
。 pTop
看起来像一个数据成员,也许您在构造函数中表示的意思是:pCurrent = new StringListNode; // Allocate new memory and point at it
pCurrent->pNext = nullptr; // Assign null to next pointer
pTop = pCurrent; // Make pTop point at new memory
并在析构函数中删除
pCurrent = new StringListNode;
,因为它不执行任何操作。输出时,您检查
pCurrent != 0
,但在读取时不检查null。 pCurrent
可能是空指针。另外,请阅读Why is iostream::eof inside a loop condition considered wrong?。您的循环应为:
while(pCurrent && (in >> pCurrent->data))
{
pCurrent = pCurrent->pNext;
}