仅当我输入10个或更多3和7的数字时才会显示。它来自下面的此方法，我没有使用此方法进行了测试。这是代码
Scanner input = new Scanner(System.in);
System.out.print("Enter a positive integer...");
int num = input.nextInt();
// Outputs
System.out.println("Number of digits in number is " + numberDigits(num));
System.out.println("Number begins with " + firstNum(num));
System.out.println("Number ends with " + lastNum(num));
System.out.println("Does number begin with 7? " + beginWith(num, 7));
System.out.println("Does number begin with 3? " + beginWith(num, 3));
System.out.println("Does number contain a 7? " + contains(num, 7));
System.out.println("Does number contain a 3? " + contains(num, 3));
System.out.println("Is the number divisible by 13? " + divTest(num, 13));
System.out.println("Is the number divisible by 77? " + divTest(num, 77));
System.out.println("How many times does 7 appear in the number? " + digitAppearances(num, 7));
System.out.println("How many times does 3 appear in the number? " + digitAppearances(num, 3));
public static int digitAppearances(int num, int x) {
// Check if num is 0
if (num <= 0 ) {
return 0;
}
// Count number of times x appears
else if (num % 10 == x) {
return 1 + digitAppearances(num / 10, x);
}
else {
return digitAppearances(num / 10, x);
}
}
最佳答案
Scanner尝试使用the int method读取nextInt。
调用此格式为nextInt()的方法的行为与调用nextInt(radix)的行为完全相同，其中radix是此扫描程序的默认基数。
nextInt（基数）：
抛出：
InputMismatchException-如果下一个标记与Integer正则表达式不匹配或超出范围
如果输入的值大于Integer.MAX_VALUE（约21亿，10位数字），则将得到InputMismatchException。
如果要输入最多19位数字，请使用nextLong。
如果要输入任意位数，只需调用next，获取字符串，并验证它仅包含数字即可。您需要先将字符数字转换为数字类型，然后再进行进一步处理。
关于java - Java InputMismatchException错误。我将如何解决这个问题？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/49640214/