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7年前关闭。
//这是一个小代码,用于研究集合的工作原理,但是当我在main方法中创建Mountain对象时,会出现错误。最后进一步解释。
上面的代码在没有错误的情况下编译正常,但是当我想在main方法中创建Mountain对象时,出现错误“无法从静态方法引用非静态”
如果不这样做,则每个
有关更多讨论,请参见:
Java: Static vs non static inner class
Java inner class and static nested class
7年前关闭。
//这是一个小代码,用于研究集合的工作原理,但是当我在main方法中创建Mountain对象时,会出现错误。最后进一步解释。
import java. util. * ;
public class sortMountains {
class Mountain {
String name;
int height;
Mountain(String n, int h) {
name = n;
height = h;
}
public String toString( ) {
return name + + height;
}
}
List<Mountain> mtn = new ArrayList<Mountain> ();
class NameCompare implements Comparator <Mountain> {
public int compare(Mountain one, Mountain two) {
return one.name. compareTo(two. name);
}
}
class HeightCompare implements Comparator <Mountain> {
public int compare(Mountain one, Mountain two) {
return (two. height - one. height) ;
}
}
public void go() {
mtn.add(new Mountain("Longs ", 14255));
mtn.add(new Mountain("Elbert ", 14433));
mtn.add(new Mountain("Maroon " , 14156));
mtn.add(new Mountain("Castle ", 14265));
System.out.println("as entered:\n" + mtn);
NameCompare nc = new NameCompare();
Collections.sort(mtn, nc);
System.out.println("by name:\n'" + mtn);
HeightCompare hc = new HeightCompare();
Collections.sort(mtn, hc);
System.out.println("by height:\n " + mtn);
}
public static void main(String args[]){
sortMountains sorting=new sortMountains();
sorting.go();
//error line Mountain a=new Mountain("Everest",12121);
}
}
上面的代码在没有错误的情况下编译正常,但是当我想在main方法中创建Mountain对象时,出现错误“无法从静态方法引用非静态”
最佳答案
使Mountain
类static
如下所示:
static class Mountain {
...
如果不这样做,则每个
Mountain
实例都必须具有一个与之关联的sortMountains
实例。由于main()
中没有这样的实例(方法本身是static
),因此编译器不允许您在其中实例化Mountain
。有关更多讨论,请参见:
Java: Static vs non static inner class
Java inner class and static nested class
关于java - 不允许在main方法中声明,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/13507952/
10-11 05:12