我试图在GWT项目中使用RESTEasy实现REST服务,但是当我进入相应的URI时,应用程序将返回:

Grave: failed to execute
javax.ws.rs.NotFoundException: Could not find resource for full path: http://127.0.0.1:8888/api/matches
    at org.jboss.resteasy.core.registry.ClassNode.match(ClassNode.java:73)
    at org.jboss.resteasy.core.registry.RootClassNode.match(RootClassNode.java:48)
    at org.jboss.resteasy.core.ResourceMethodRegistry.getResourceInvoker(ResourceMethodRegistry.java:444)
    at org.jboss.resteasy.core.SynchronousDispatcher.getInvoker(SynchronousDispatcher.java:234)
    at org.jboss.resteasy.core.SynchronousDispatcher.invoke(SynchronousDispatcher.java:171)
    at org.jboss.resteasy.plugins.server.servlet.ServletContainerDispatcher.service(ServletContainerDispatcher.java:220)
    at org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:56)
    at org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:51)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

我的web.xml是:
<?xml version="1.0" encoding="UTF-8" standalone="no"?><web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee                http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

  <!-- All REST resources will be prefixed by /api -->
  <context-param>
    <param-name>resteasy.servlet.mapping.prefix</param-name>
    <param-value>/api</param-value>
  </context-param>

  <!-- Servlets -->
  <servlet>
    <servlet-name>Resteasy</servlet-name>
    <servlet-class>org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher</servlet-class>
    <init-param>
        <param-name>javax.ws.rs.Application</param-name>
        <param-value>eii.api.MatchApplication</param-value>
    </init-param>
  </servlet>

  <!-- Servlet mappings -->
  <!-- All calls to /api/xxx will be sent to the reasy servlet -->
  <servlet-mapping>
    <servlet-name>Resteasy</servlet-name>
    <url-pattern>/api/*</url-pattern>
  </servlet-mapping>

</web-app>

执行应用程序:
public class MatchApplication extends Application {
    private Set<Object> singletons = new HashSet<Object>();
    private Set<Class<?>> classes = new HashSet<Class<?>>();

    public MatchApplication() {
        singletons.add(new MatchServiceImpl());
    }

    @Override
    public Set<Class<?>> getClasses() {
        return classes;
    }

    @Override
    public Set<Object> getSingletons() {
        return singletons;
    }
}

这是提供REST服务的类:
 /* Imports */
    ...
@Path("/matches")
public class MatchResource {
    private static MatchResource _instance = null;
    private MatchRepository repository;

    public MatchResource() {
        repository = new MapMatchRepository();
    }

    public static MatchResource getInstance() {
        if (_instance == null)
            _instance = new MatchResource();
        return _instance;
    }

    @GET
    @Path("/{id}")
    @Produces("application/json")
    public Match getMatch(@PathParam("id") int id) {
        return repository.getMatch(id);
    }

    @GET
    @Produces("application/json")
    public Matches getMatchesCurrentRound() {
        return repository.getMatchesCurrentRound();
    }

        ...
}

我想要的是进入时返回JSON文件,例如:http://127.0.0.1:8888/api/matches
有人知道我在做什么错吗?

编辑:

如果我访问http://127.0.0.1:8888/api/http://127.0.0.1:8888/api/*(其中*是您要编写的内容),浏览器将不显示任何内容。但是,如果我访问http://127.0.0.1:8888/oqiwn(其中oqiwn是随机字符串),则浏览器将显示Error 404

另外,我尝试了RESTClient插件,这些是返回的答案:

使用http://127.0.0.1:8888/api/http://127.0.0.1:8888/api/*
Status Code: 404 Not Found
Cache-Control: no-cache
Content-Length: 0
Date: Sun, 10 Nov 2013 22:59:57 GMT
Expires: Fri, 01 Jan 1990 00:00:00 GMT
Server: Development/1.0

并带有http://127.0.0.1:8888/oqiwn
Status Code: 404 Not Found
Cache-Control: no-cache
Content-Length: 83
Content-Type: text/html; charset=iso-8859-1
Date: Sun, 10 Nov 2013 22:59:05 GMT
Expires: Fri, 01 Jan 1990 00:00:00 GMT
Server: Development/1.0

注意Content-Type: text/html; charset=iso-8859-1不在第一个中。

最佳答案

您使用名为getMatches()的方法添加了资源,Resteasy一无所知。您需要覆盖getSingletons()Application方法,并从那里返回根资源,如下所示。

Documentation Here

示例:

public class MatchApplication extends Application {
    private Set<Object> singletons = new HashSet<Object>();
    private Set<Class<?>> classes = new HashSet<Class<?>>();

    public MatchApplication() {
        singletons.add(new MatchServiceImpl());
    }

    @Override
    public Set<Class<?>> getClasses() {
        return classes;
    }

    @Override
    public Set<Object> getSingletons() {
        return singletons;
    }
}

10-06 01:48