Question :This a program for snake and ladder.the user enters the number of players and players name.
-程序不是从调用throwdice()方法的位置执行的。
package practical1;
import java.util.ArrayList;
import java.util.Scanner;
public class snakeandladder1 {
int totalpos=100;
int v;
int[] scores = new int[100];
int score=0;
int l=0;
public int throwdice() //to calculate the dice value
{
int i=0;
{
while(i==0)
{
i=(int)Math.random()*100;
i=i%13;
}
return i;
}
}
public int ladder(int score) //to check if the user has reached a ladder
{
if(score==15)
score=30;
else if(score == 45)
score=71;
else if(score == 25)
score=62;
else if(score == 81)
score=91;
else if(score == 9)
score=39;
scores[l]=score;
return score;
}
public int snake(int score) //to check if the user has reached a snake
{
if(score == 29)
score=11;
else if(score == 81)
score=48;
else if(score == 92)
score=71;
else if(score == 30)
score=6;
else if(score == 58)
score=19;
scores[l]=score;
return score;
}
void start()
{
System.out.println("Enter the number of players:");
Scanner in=new Scanner(System.in);
int n=in.nextInt();
System.out.println("Enter Players names in order:");
ArrayList<String> name1=new ArrayList<String>(); //an array to store players names
for (int i=0;i<n;i++)
{
Scanner in1=new Scanner(System.in);
String name2=in1.nextLine();
name1.add(name2);
}
while(true)
{
while(l<n) //for each player
{
System.out.println("Click y to roll dice");
Scanner in2=new Scanner(System.in);
String yes=in2.nextLine();
if (yes == "y") //------!!!This part is not getting executed
{ // It is taking y but not going further.It does not print
v=throwdice(); //anything also
System.out.println("dice value:"+v);
}
score = scores[l]+v; //the value of dice is added to individual score
if(score==totalpos) //checking if reached 100
{
System.out.println("User:"+name1.get(l)+" got "+v+".Winner!!!");
break;
}
else if(score > totalpos) //checking if dice value is more than required to 100
{
scores[l]=scores[l];
}
int s1;
s1=ladder(score); //ladder is called, if true valuue is added to score[i] in the function itself
if(s1==score)
{
snake(score); //if not ladder then snake is called
}
System.out.println("Current score of "+name1.get(l)+" is:"+scores[l]); //to display result
l++;
}
if(l==n)
{
l=0;
}
}
}
public static void main(String[] args) throws Exception{
// TODO Auto-generated method stub
snakeandladder1 sal=new snakeandladder1();
sal.start();
}
}
我得到的输出:
输入玩家人数:
2
按顺序输入玩家名称:
抹布
吻
单击y掷骰子
ÿ
抹布的当前得分是:0
单击y掷骰子
ÿ
kis当前得分是:: 0
单击y掷骰子
ÿ
抹布的当前得分是:0
单击y掷骰子
请帮忙 ..
最佳答案
您的代码中存在一些问题...首先,我建议您坚持正确的Java用法,最佳实践,命名约定,异常处理。.从您的类名开始。 。
关于你的问题
1:
if (yes == "y") {}
应该更改为:
if (yes.equalsIgnoreCase("y")) {}
在这种情况下,我使用“ rert588”的上述答案。
2:throwdice()方法中有几个问题。我看到您当前的方法进入永无休止的while循环,因为我始终为“ 0”。我不清楚您要实现什么目标,但我认为应该像下面这样。
应该更改为:
public int throwdice() //to calculate the dice value
{
int i = (int)(Math.random() * 100); // make note on your Casting.
i = i % 13;
return i;
}
尝试一下,希望对您有所帮助。