我试图解析下面的json
并在第150行捕获到JSONException
(在代码中标记),但我无法找出它发生的原因。目的是查找特定包装的测试列表并将其存储在arraylist
中。
当我将screen_package作为第二个参数传递时,日志消息是:java.lang.string类型的value screen_package无法转换为jsonobject。根据我的理解,我们可以在String
的构造函数中传递JSONObject
对象。如果我错了,请纠正我。看一看
{
"package_name": {
"camera_package": {
"RearCamera": {
"test_name": "RearCamera",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "RearCamera",
"test_category": "manual",
"order": "42"
},
"FrontCamera": {
"test_name": "FrontCamera",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "FrontCamera",
"test_category": "manual",
"order": "43"
},
"Flash": {
"test_name": "Flash",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "Flash",
"test_category": "manual",
"order": "1"
},
"AutoFocus": {
"test_name": "AutoFocus",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "AutoFocus",
"test_category": "manual",
"order": "35"
},
"VideoRecord": {
"test_name": "VideoRecord",
"test_type": "mandatory",
"visibility": "true",
"report_name": "VideoRecord",
"test_category": "manual",
"order": "10"
},
"FrontVideoRecorder": {
"test_name": "FrontVideoRecorder",
"test_type": "mandatory",
"visibility": "true",
"report_name": "FrontVideoRecorder",
"test_category": "manual",
"order": "11"
}
},
"screen_package": {
"Screen": {
"test_name": "Screen",
"test_type": "Mandatory",
"visibility": "true",
"report_name": "Screen",
"test_category": "manual",
"order": "21"
}
}
}
}
以下是Java代码:
public void parseJSON(String jsonName, String packageName) {
try {
JSONObject jsonRootObject = new JSONObject(jsonName);
if (jsonRootObject != null && jsonRootObject.length() > 0) {
Iterator<String> packageKeys = jsonRootObject.keys();
if (packageKeys != null) {
while(packageKeys.hasNext()){
String currentPackageKey = packageKeys.next();
if(currentPackageKey!= null && currentPackageKey.length()>0 &&
currentPackageKey.equals(packageName)){
JSONObject jsonPackageObject = new JSONObject(currentPackageKey); //line 150
if(jsonPackageObject!=null && jsonPackageObject.length()>0) {
Iterator<String> testNameKeys = jsonPackageObject.keys();
if(testNameKeys!=null){
while(testNameKeys.hasNext()) {
String currentTestNameKey = testNameKeys.next();
if(currentTestNameKey!=null && currentTestNameKey.length()>0) {
//do something
}
}
}
}
}
}
}
}
} catch (JSONException e) {
e.printStackTrace();
System.out.println("Exception caught : "+e.getLocalizedMessage());
}
}
最佳答案
JSONException
表示在json处理期间发生了一些异常。
你应该使用getJSONObject(String name)
。
JSONObject getJSONObject (String name)
返回由名称映射的值,如果它存在并且是JSONObjor,或
否则抛出
代码结构
JSONObject screen_package = jsonobject.getJSONObject("screen_package");
关于android - 正在获取JSONException?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/48186971/