java - Java是否支持带引用的JSON序列化？

我正在寻找可以根据JSPON specification.处理引用的Java JSPON序列化程序

目前有没有可以做的事情？还是有任何方法可以修改现有的序列化器以使用$ ref表示法处理对象引用？

最佳答案

注意：我是EclipseLink JAXB (MOXy)负责人，也是JAXB 2 (JSR-222)专家组的成员。

如果您对对象-JSON绑定方法感兴趣，请使用MOXy。以下示例基于JSPON核心规范中的示例一：

http://www.jspon.org/JSPON_Core_Spec.htm

父母

Parent类是与JSON消息的根相对应的域对象。它具有两个Child类型的字段。

package forum9862100;

import javax.xml.bind.annotation.*;

@XmlAccessorType(XmlAccessType.FIELD)
public class Parent {

    protected Child field1;
    protected Child field2;

}

儿童

Child类可以由其键引用。我们将使用XmlAdapter处理该用例。我们通过XmlAdapter注释链接到@XmlJavaTypeAdapter。

package forum9862100;

import javax.xml.bind.annotation.*;
import javax.xml.bind.annotation.adapters.XmlJavaTypeAdapter;

@XmlJavaTypeAdapter(ChildAdapter.class)
@XmlAccessorType(XmlAccessType.FIELD)
public class Child {

    protected String id;
    protected String foo;
    protected Integer bar;

}

子适配器

下面是XmlAdapter的实现。该XmlAdapter是有状态的，这意味着我们需要在Marshaller和Unmarshaller上设置一个实例。

package forum9862100;

import java.util.*;

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.adapters.XmlAdapter;

public class ChildAdapter extends XmlAdapter<ChildAdapter.AdaptedChild, Child>{

    private List<Child> childList = new ArrayList<Child>();
    private Map<String, Child> childMap = new HashMap<String, Child>();

    public static class AdaptedChild extends Child {
        @XmlElement(name="$ref")
        public String reference;
    }

    @Override
    public AdaptedChild marshal(Child child) throws Exception {
        AdaptedChild adaptedChild = new AdaptedChild();
        if(childList.contains(child)) {
            adaptedChild.reference = child.id;
        } else {
            adaptedChild.id = child.id;
            adaptedChild.foo = child.foo;
            adaptedChild.bar = child.bar;
            childList.add(child);
        }
        return adaptedChild;
    }

    @Override
    public Child unmarshal(AdaptedChild adaptedChild) throws Exception {
        Child child = childMap.get(adaptedChild.reference);
        if(null == child) {
            child = new Child();
            child.id = adaptedChild.id;
            child.foo = adaptedChild.foo;
            child.bar = adaptedChild.bar;
            childMap.put(child.id, child);
        }
        return child;
    }

}

演示版

以下代码演示了如何在XmlAdapter和Marshaller上指定有状态的Unmarshaller：

package forum9862100;

import java.io.File;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;

public class Demo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Parent.class);

        StreamSource json = new StreamSource(new File("src/forum9862100/input.json"));
        Unmarshaller unmarshaller = jc.createUnmarshaller();
        unmarshaller.setProperty("eclipselink.media-type", "application/json");
        unmarshaller.setProperty("eclipselink.json.include-root", false);
        unmarshaller.setAdapter(new ChildAdapter());
        Parent parent = (Parent) unmarshaller.unmarshal(json, Parent.class).getValue();

        System.out.println(parent.field1 == parent.field2);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty("eclipselink.media-type", "application/json");
        marshaller.setProperty("eclipselink.json.include-root", false);
        marshaller.setAdapter(new ChildAdapter());
        marshaller.marshal(parent, System.out);
    }

}

输出量

以下是运行演示代码的输出。请注意Child的两个实例如何通过身份测试。

true
{
   "field1" : {
      "id" : "2",
      "foo" : "val",
      "bar" : 4
   },
   "field2" : {
      "$ref" : "2"
   }}