java - 将Popup设置为wrap_content后如何获得高度？

喂，

我有这个弹出窗口：

    // Inflate the popup_layout.xml
    LinearLayout viewGroup = (LinearLayout) context.findViewById(R.id.popup);
    LayoutInflater layoutInflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    final View layout = layoutInflater.inflate(R.layout.day_popup_date, viewGroup);

    layout.measure(View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED),
            View.MeasureSpec.makeMeasureSpec(0, View.MeasureSpec.UNSPECIFIED));

    int popupWidth = width;
    final int popupHeight = height;

    // Creating the PopupWindow
    final PopupWindow popup = new PopupWindow(context);

    popup.setContentView(layout);
    popup.setWidth(popupWidth);
    popup.setHeight(ListPopupWindow.WRAP_CONTENT);
    popup.setFocusable(false);

如您所见，popup.setHeight（ListPopupWindow.WRAP_CONTENT）;设置为包装内容。

但是，如果尺寸小于100px，我想将弹出窗口扩大到600px。

我怎样才能做到这一点？

谢谢 ：-）

最佳答案

简单地写...

 popup.setHeight(600);