我试图模拟这个website page
我的输入表如下:
现在,从输入表中提取值并按升序排列后,我在临时工作表中得到:
这就是我的结果表:
现在,我已经在排序过程后尝试了此操作(没有添加排序代码,因为这不是问题所在):
Set rng = Union(wTime.Range("D6:D25"), wTime.Range("F6:F25"), wTime.Range("H6:H25"), wTime.Range("J6:J25"))
cnt1 = 1: cnt2 = 1: cnt3 = 1: cnt4 = 1
wTime.Range("A6:A25") = Empty 'Ticker
For i = 1 To 20
bckStroke(i) = wTemp.Range("A" & i + 1).Value
brstStroke(i) = wTemp.Range("C" & i + 1).Value
btrFly(i) = wTemp.Range("E" & i + 1).Value
frStyle(i) = wTemp.Range("G" & i + 1).Value
wTime.Range("A6:A25") = Empty
For Each cel In rng
If cel.Column = 4 And cel.Value = bckStroke(i) And cel.Value <> 0 And Trim(wTime.Cells(cel.Row, 1)) <> "Y" And cnt1 < 6 Then
wRes.Cells((cnt1 + 5 + (cnt1 - 1) * 2) - 1, 4) = wTime.Cells(cel.Row, 2) 'Athlete Name
wRes.Cells(cnt1 + 5 + (cnt1 - 1) * 2, 4) = bckStroke(i) 'Time
cnt1 = cnt1 + 1
wTime.Cells(cel.Row, 1) = "Y"
End If
If cel.Column = 6 And cel.Value = brstStroke(i) And cel.Value <> 0 And Trim(wTime.Cells(cel.Row, 1)) <> "Y" And cnt2 < 6 Then
wRes.Cells((cnt2 + 5 + (cnt2 - 1) * 2) - 1, 6) = wTime.Cells(cel.Row, 2) 'Athlete Name
wRes.Cells(cnt2 + 5 + (cnt2 - 1) * 2, 6) = brstStroke(i) 'Time
cnt2 = cnt2 + 1
wTime.Cells(cel.Row, 1) = "Y"
End If
If cel.Column = 8 And cel.Value = btrFly(i) And cel.Value <> 0 And Trim(wTime.Cells(cel.Row, 1)) <> "Y" And cnt3 < 6 Then
wRes.Cells((cnt3 + 5 + (cnt3 - 1) * 2) - 1, 8) = wTime.Cells(cel.Row, 2) 'Athlete Name
wRes.Cells(cnt3 + 5 + (cnt3 - 1) * 2, 8) = btrFly(i) 'Time
cnt3 = cnt3 + 1
wTime.Cells(cel.Row, 1) = "Y"
End If
If cel.Column = 10 And cel.Value = frStyle(i) And cel.Value <> 0 And Trim(wTime.Cells(cel.Row, 1)) <> "Y" And cnt4 < 6 Then
wRes.Cells((cnt4 + 5 + (cnt4 - 1) * 2) - 1, 10) = wTime.Cells(cel.Row, 2) 'Athlete Name
wRes.Cells(cnt4 + 5 + (cnt4 - 1) * 2, 10) = frStyle(i) 'Time
cnt4 = cnt4 + 1
wTime.Cells(cel.Row, 1) = "Y"
End If
Next cel
Next i
我只想知道最简单的逻辑,以获得期望的结果后,安排升序(参考临时表)应该很容易,但我似乎无法理解。
我现在知道的情况是:
每队应有独特的游泳运动员(即每队有4个独特的名字)
如果一个游泳运动员在其他组别中也有最好的表现,他也可以出现在其他组别中。(例如,马塞洛将出现在前4名,因为他在所有4个类别中都有最好的时间)
时间最短的小组应列在结果表的第一位我认为按升序排序可以解决这个问题,关键是从临时工单列表中选择合适的游泳者。
最佳答案
编辑:
四中继逻辑前提:在没有两个相同字符串的情况下获得所有可能的组合。然后把它们从低到大排序。我将执行以下操作:获取所有可能的组合及其和,如下所示:*组合可能仍然是错误的,因为它可能随您拥有多少数字而变化。这只是一个描述过程的指南
Sub Combinations()
Dim i As Long, j As Long, k As Long, l As Long, m As Long, n As Long, o As Long, p As Long, q As Long
Dim CountComb As Long, lastrow As Long
Range("K2").Value = Now - 5
Application.ScreenUpdating = False
CountComb = 0: lastrow = 6
For i = 1 To 6: For j = 1 To 5
For k = 1 To 6: For l = 1 To 6
If Not (i = j Or i = k Or i = l Or j = k Or j = l Or k = l) Then
Range("K" & lastrow).Value = Range("A" & i).Value & "/" & _
Range("B" & j).Value & "/" & _
Range("C" & k).Value & "/" & _
Range("D" & l).Value
lastrow = lastrow + 1
CountComb = CountComb + 1
End If
Next: Next
Next: Next
Range("K1").Value = CountComb
Range("K3").Value = Now + 21
Application.ScreenUpdating = True
End Sub
Function TimeSum(Persons As String, Chr As String) As Double
Dim ArrayPersons() As String: ArrayPersons = Split(Persons, Chr)
Dim SumOfTime As Double
Dim ItemPerson As Variant
Dim NumberRoutines As Long: NumberRoutines = 2
Const SheetData = "Sheet1"
For Each ItemPerson In ArrayPersons
SumOfTime = Sheets(SheetData).Columns(NumberRoutines).Find(ItemPerson).Offset(0, -1).Value + SumOfTime
NumberRoutines = NumberRoutines + 2
Next ItemPerson
TimeSum = SumOfTime
End Function
也许你可以定义更好的子来做你想做的事情,但是,最后的代码可以引导你走上正确的道路。再想一想,你可以在字典里找到组合词。
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