我得到了以下任务:创建一个包含男人,女人和未知名称的文本文件。尝试实现一个过滤器,将那些名称与真实名称进行比较(因此,总共输入了3个文件:男性,女性,比如说房客)。过滤时,将匹配的名称放入其适当的容器中。在我看来,这很简单,所以我按照下面提供的方式进行了操作。
我的问题是:有没有一种方法可以优化此代码?
我尝试使用抽象类,并基于抽象实体创建4个不同的对象(男人,女人,已知,未知)。但是对于这样一个简单的任务,代码量仍然很大。另一个想法是使用lambda表达式,但是我仅限于C ++ 98。
我想我想得太多了...
#include <fstream>
#include <iostream>
#include <vector>
#include <string>
int main()
{
std::ifstream men("resources/men_names.txt");
std::ifstream women("resources/women_names.txt");
std::ifstream renters("resources/renter_names.txt");
std::vector<std::string> menNames;
std::vector<std::string> womenNames;
std::vector<std::string> renterNames;
std::vector<std::string> knownRenters;
std::vector<std::string> unknownRenters;
std::string name;
while (men >> name)
menNames.push_back(name);
men.close();
while (women >> name)
womenNames.push_back(name);
women.close();
while (renters >> name)
renterNames.push_back(name);
renters.close();
std::vector<std::string>::iterator itMen;
std::vector<std::string>::iterator itWomen;
std::vector<std::string>::iterator itRenters;
for (itRenters = renterNames.begin(); itRenters != renterNames.end(); itRenters++)
{
bool found = false;
for (itMen = menNames.begin(); itMen != menNames.end(); itMen++)
{
if ((*itMen) == (*itRenters))
{
found = true;
knownRenters.push_back((*itMen));
}
}
if (!found)
{
for (itWomen = womenNames.begin(); itWomen != womenNames.end(); itWomen++)
{
if ((*itWomen) == (*itRenters))
{
found = true;
knownRenters.push_back((*itWomen));
}
}
}
if (!found)
unknownRenters.push_back((*itRenters));
}
std::cout << knownRenters.size() << '\n';
std::cout << unknownRenters.size() << '\n';
std::cin.get();
return 0;
}
最佳答案
缩短现有代码。这应该都是C ++ 98
#include <fstream>
#include <iostream>
#include <vector>
#include <string>
#include <set>
#include <iterator>
int main()
{
std::ifstream men("resources/men_names.txt");
std::ifstream women("resources/women_names.txt");
std::set<std::string> peopleNames;
peopleNames.insert(std::istream_iterator<std::string>(men), std::istream_iterator<std::string>());
peopleNames.insert(std::istream_iterator<std::string>(women), std::istream_iterator<std::string>());
std::ifstream renters("resources/renter_names.txt");
std::vector<std::string> knownRenters;
std::vector<std::string> unknownRenters;
for (std::string name; renters >> name; )
{
if (peopleNames.count(name))
knownRenters.push_back(name);
else
unknownRenters.push_back(name);
}
std::cout << knownRenters.size() << '\n';
std::cout << unknownRenters.size() << '\n';
std::cin.get();
return 0;
}
关于c++ - 在C++ 98中优化 vector 的过滤,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/50275670/