我有这样的问题。我正在使用DBsetup进行春季启动测试和postgresql数据库。而且我正在使用DBsetup设置用户,但是当我尝试通过spring数据设置另一个用户时,我遇到下一个异常:
Подробности: Key (id)=(1) already exists.
org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [users_pkey];
这是我的测试课:
@RunWith(SpringRunner.class)
@SpringBootTest
@TestPropertySource("/application-test.properties")
public class UserRepositoryTest {
@Autowired
private ApplicationContext applicationContext;
@Autowired
private UserRepository userRepository;
@Autowired
private DataSource dataSource;
@Before
public void insertData() throws SQLException {
Operation operation = sequenceOf(CommonOperations.DELETE_ALL, CommonOperations.INSERT_USER);
DbSetup dbSetup = new DbSetup(new DataSourceDestination(dataSource), operation);
dbSetup.launch();
}
@After
public void cleanPK() throws SQLException {
DBUtil.resetAutoIncrementColumns(applicationContext, "user");
}
@Test
public void registerUser() {
val user = new User(null, "Glass", "123123", "[email protected]");
assertEquals(user, userRepository.saveAndFlush(user));
}
}
DBsetup的操作:
public class CommonOperations {
public static final Operation DELETE_ALL = deleteAllFrom("article_tag", "article", "tag", "users");
public static final Operation INSERT_USER =
insertInto("users")
.columns("id", "email", "password", "username")
.values(1, "[email protected]", "123123", "Daimon")
.build();
}
重置序列的类:
@NoArgsConstructor
public final class DBUtil {
public static void resetAutoIncrementColumns(ApplicationContext applicationContext,
String... tableNames) throws SQLException {
DataSource dataSource = applicationContext.getBean(DataSource.class);
String resetSqlTemplate = "ALTER SEQUENCE %s RESTART WITH 1;";
try (Connection dbConnection = dataSource.getConnection()) {
for (String resetSqlArgument: tableNames) {
try (Statement statement = dbConnection.createStatement()) {
String resetSql = String.format(resetSqlTemplate, resetSqlArgument + "_id_seq");
statement.execute(resetSql);
}
}
}
}
}
有谁知道如何解决这个问题?
最佳答案
要看的一件事:
public static final Operation INSERT_USER =
insertInto("users")
.columns("id", "email", "password", "username")
.values(1, "[email protected]", "123123", "Daimon")
.build();
在这里,您使用的是硬编码ID,即
1
现在,在测试用例中,当您尝试创建另一个用户时,您将id传递为null,并假设该id是从序列中选择的。它也将从
1
开始。因此,您会遇到冲突。