例如，libphonenumber ++++++614- -12a345678(())&认为以下（无效）AU手机号码是有效的：
Tested in their demo site：
明智的代码：
final String mobilePhoneNumber = "++++++614- -12a345678(())&";
final String region = "AU";
final PhoneNumberUtil phoneNumberUtil = PhoneNumberUtil.getInstance();
// true
// I don't get it, how come ++++++614- -12a345678(())& is even considered a possible number??
System.out.println(phoneNumberUtil.isPossibleNumber(mobilePhoneNumber, region));
final Phonenumber.PhoneNumber phoneNumber = phoneNumberUtil.parse(mobilePhoneNumber, region);
// true
final boolean validNumberForRegion = phoneNumberUtil.isValidNumberForRegion(phoneNumber, region);
// true
final boolean validMobileNumber = phoneNumberUtil.getNumberType(phoneNumber).equals(PhoneNumberType.MOBILE);
在libphonenumber v8.9.2上测试：
compile group: 'com.googlecode.libphonenumber', name: 'libphonenumber', version: '8.9.2'
最佳答案
首先，编写一种使用正则表达式验证输入的方法。就像是：
boolean validPhone(String str){
str.matches("^[+]?\\d{2,4}(-?\\d{1,5}){0,2}$");
}
也可以看看：
This post, phoneregex.com和rexlib's section,