我有 flex 搜索中的文档,看起来像:
{
"entityFk": 0,
"entityCode": "ADM",
"entityObj": {
"id": 0,
"code": "ADM",
"description": "ADM - FIRSTCOM"
},
"practiceFk": 54745,
"practiceObj": {
"id": 54745,
"code": "33.04.01.32",
"description": "Artrotomia ou artroscopia com tratamento de lesões articulares circunscritas ",
"practiceValue": 23.5
}
}
}
我想对所有具有attributeCode.description等于“FIRST”的“practiceValue”(不为null)求和,因此我进行了以下查询:
{
"size" : 0,
"query" : {
"bool" : {
"must_not" : [
{
"missing" : { "field" : "practiceObj.practiceValue" }
}
],
"must" : [
{
"match" : { "entityObj.description" : "FIRST" }
}
]
}
},
"aggs" : {
"total" : {
"sum" : { "field" : "practiceObj.practiceValue"}
}
}
}
这是我获得的结果:
{
"took": 26,
"timed_out": false,
"_shards": {
"total": 5,
"successful": 5,
"failed": 0
},
"hits": {
"total": 11477,
"max_score": 0,
"hits": []
},
"aggregations": {
"total": {
"value": 1593598.7499999984
}
}
}
达成的协议(protocol)是:如何将值四舍五入到小数点后两位。
有人可以帮忙吗?
谢谢。
编辑:
这是我的映射:
{
"index_practice_entities": {
"mappings": {
"practice_entities_search": {
"properties": {
"entityCode": {
"type": "string"
},
"entityFk": {
"type": "long"
},
"entityObj": {
"properties": {
"code": {
"type": "string"
},
"description": {
"type": "string"
},
"id": {
"type": "long"
}
}
},
"practiceFk": {
"type": "long"
},
"practiceObj": {
"properties": {
"code": {
"type": "string"
},
"description": {
"type": "string"
},
"id": {
"type": "long"
},
"practiceValue": {
"type": "double"
}
}
}
}
}
}
}
}
最佳答案
请尝试以下提到的脚本,它将合计的值四舍五入到小数点后两位。
"aggs" : {
"total" : {
"sum" : {
"script" : "Math.round(doc['practiceObj.practiceValue'].value*100)/100.0"
}
}
}
关于elasticsearch - 如何四舍五入到小数点后两位至小数点-ElasticSearch,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/36041812/