c# - 洗牌与图像

我试图随机列出一个列表，然后将其放入图片框。当我这样做时，我收到错误消息“索引超出范围。必须为非负数，并且小于集合的大小”

这是随机代码：

public class Dealer
{
    public static Random rand = new Random();
    public static List<Kort> KortenÄrBlandade = new List<Kort>();
    public void Shuffle()
    {
        List<Kort> KortenÄrBlandade = new List<Kort>(deckOfCards.OrderBy(_ => rand.Next(0, deckOfCards.Count)));
    }
}

这是调用该方法的代码

private void button1_Click(object sender, EventArgs e)
{
    Spelare.Dealer deal = new Spelare.Dealer();
    deal.Shuffle();
    pictureBox1.Image = Spelare.Dealer.KortenÄrBlandade[2].img;
}

最佳答案

您可以尝试使用Fisher-Yates随机播放算法

http://en.wikipedia.org/wiki/Fisher%E2%80%93Yates_shuffle

可能是这样的：

public class Dealer {

  // Fisher-Yates shuffle algorithm with explicit generator
  private static void CoreShuffle(IList<Kort> list, Random generator) {
    if (Object.ReferenceEquals(null, list))
      throw new ArgumentNullException("list");
    else if (Object.ReferenceEquals(null, generator))
      throw new ArgumentNullException("generator");

    for (int i = list.Count - 1; i >= 0; --i) {
      int index = generator.Next(i + 1);

      Kurt h = list[index];
      list[index] = list[i];
      list[i] = h;
    }
  }

  public static Random rand = new Random(); // <- Be careful: Random is not thread safe; readonly is also a good addition here

  // Return new shuffled list based on deckOfCards
  public List<Kort> ShuffledList() {
    List<Kort> result = new List<Kort>(deckOfCards); // <- Check this line in your code
    CoreShuffle(result, rand);

    return result;
  }