python - 在python中生成正弦波声音

我一直在尝试使用以下代码生成正弦波，并以我的扬声器播放它，但这听起来太可怕了。有人知道为什么吗？它听起来不像正弦波。

       dur = int(FS * float(duration) / 1000)
       for i in range(dur):
         a = frequency * i * 2 * math.pi / FS
         y = math.sin(a)
         outbuf[i] = y * 0.2

p = pyaudio.PyAudio()
stream = p.open(format=pyaudio.paFloat32, channels=1, rate=44100, output=True)
stream.write(outbuf)
stream.stop_stream()
stream.close()
p.terminate()

play_sound("sine", 1000, 1, 1000)

最佳答案

音频缓冲区必须打包为二进制文件，对于python3，请使用b''.join(struct.pack还通过将 Angular theta增量常数移到循环外部简化了sin曲线的合成

import pyaudio
import numpy as np
import math
import struct

FS = 44100  #  frames per second, samples per second or sample rate

def play_sound(type, frequency, volume, duration):

   generate_sound(type, frequency, volume, duration)

def generate_sound(type, frequency, volume, duration):

    outbuf = np.random.normal(loc=0, scale=1, size=int(float(duration / 1000.0)*FS))

    if type == "sine":
        dur = int(FS * float(duration / 1000.0))
        theta = 0.0
        incr_theta = frequency * 2 * math.pi / FS # frequency increment normalized for sample rate
        for i in range(dur):
            outbuf[i] = volume * math.sin(theta)
            theta += incr_theta

    p = pyaudio.PyAudio()
    stream = p.open(format=pyaudio.paFloat32, channels=1, rate=FS, output=True)
    data = b''.join(struct.pack('f', samp) for samp in outbuf) # must pack the binary data
    stream.write(data)
    stream.stop_stream()
    stream.close()
    p.terminate()

play_sound("sine", 220, 0.8, 1000)  #  duration in milliseconds

关于python - 在python中生成正弦波声音，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/61576953/