我正在使用Spring 4.2.3 AsyncRestTemplate.exchange()来调用一些API,这将花费几秒钟,并且我希望listenableFuture.get(1,TimeUnit.SECONDS)将阻塞1秒钟,然后抛出TimeOutException。
相反,发生的是listenableFuture.get()将在api调用的整个时间(超过1秒)内阻塞
AsyncRestTemplate restTemplate = new AsyncRestTemplate();
ListenableFuture<ResponseEntity<String>> listenableFuture = restTemplate.exchange(URL, HttpMethod.GET, null, String.class);
log.debug("before callback");
//...add callbacks
try{
log.debug("before blocking");
listenableFuture.get(1, TimeUnit.SECONDS);
}catch (InterruptedException e) {
log.error(":GOT InterruptedException");
} catch (ExecutionException e) {
log.error(":GOT ExecutionException");
} catch (TimeoutException e) {
log.info(":GOT TimeoutException");
}
log.info("FINISHED");
输出:
09:15:21.596 DEBUG [main] org.springframework.web.client.AsyncRestTemplate:78 - Created asynchronous GET request for "http://localhost:4567/oia/wait?seconds=5"
09:15:21.666 DEBUG [main] org.springframework.web.client.RestTemplate:720 - Setting request Accept header to [text/plain, application/xml, text/xml, application/json, application/*+xml, application/*+json, */*]
09:15:21.679 DEBUG [main] com.zazma.flow.utils.FutureTest:74 - before callback
09:15:21.679 DEBUG [main] com.zazma.flow.utils.FutureTest:95 - before blocking
09:15:26.709 DEBUG [main] org.springframework.web.client.AsyncRestTemplate:576 - Async GET request for "http://localhost:4567/oia/wait?seconds=5" resulted in 200 (OK)
09:15:26.711 DEBUG [main] org.springframework.web.client.RestTemplate:101 - Reading [java.lang.String] as "text/html;charset=utf-8" using [org.springframework.http.converter.StringHttpMessageConverter@3a44431a]
09:15:26.717 INFO [main] com.zazma.flow.utils.FutureTest:105 - FINISHED
这是一个示例,当不由AsyncRestTemplate创建时,ListenableFuture.get()将按预期工作
SimpleAsyncTaskExecutor te = new SimpleAsyncTaskExecutor();
ListenableFuture<String> lf = te.submitListenable(() -> {
Thread.sleep(8000);
return "OK";
});
lf.get(1, TimeUnit.SECONDS);
最佳答案
您的代码是完全正确的。引起问题的是Spring框架中的错误。虽然,我没有在spring的问题跟踪器中找到它(或者可能没有进行记录),但是您可以通过更新依赖项来解决它。当然,您的代码将适用于spring-web> = 4.3.2.RELEASE的版本。
关于java - 超时阻止在ListenableFuture上,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/42267408/