我想做一个MySQL查询。我有4张桌子:A,B,C,D。
我想得到一个共同的价值:从“帐户” = 1的所有4个表中“获胜”,然后按大多数“获胜”排序。并且所有订购的“获胜”都以3为限。
如果您能帮助我,我将非常高兴。
我尝试过这样的事情:
SELECT o.*
FROM (
(SELECT wins FROM 'A')
UNION ALL
(SELECT wins FROM 'B')
UNION ALL
(SELECT wins FROM 'C')
UNION ALL
(SELECT wins FROM 'D')
UNION ALL
(SELECT * FROM 'A'
WHERE
account=1)
) AS o
ORDER BY wins DESC
但这确实是错误的。
最佳答案
如果您需要知道从中获得结果的表,请执行以下操作:
SELECT *
FROM ( SELECT wins, 'Table A' AS DataTable
FROM TableA
WHERE account = 1
UNION ALL
SELECT wins, 'Table B'
FROM TableB
WHERE account = 1
UNION ALL
SELECT wins, 'Table C'
FROM TableC
WHERE account = 1
UNION ALL
SELECT wins, 'Table D'
FROM TableD
WHERE account = 1) AS X
ORDER BY wins
LIMIT 3
如果那并不重要,那么您只需要最高的
wins
即可:SELECT *
FROM ( SELECT wins
FROM TableA
WHERE account = 1
UNION
SELECT wins
FROM TableB
WHERE account = 1
UNION
SELECT wins
FROM TableC
WHERE account = 1
UNION
SELECT wins
FROM TableD
WHERE account = 1) AS X
ORDER BY wins DESC
LIMIT 3