我有如下代码:

authRepository.login(userName, password)
              .doOnSubscribe(__ -> apiProgress.setValue(ApiProgress.start()))
              .doFinally(() -> apiProgress.setValue(ApiProgress.stop()))
              .subscribe(login -> loginData.setValue(login),
                           err -> apiError.setValue(ApiError.create(err)))


我需要对所有api调用重复doOnSubscribe(..)doFinally

有什么办法可以实现这一目标?

最佳答案

欢迎来到StackOverflow! https://stackoverflow.com/conduct

您可以使用Transformerhttp://reactivex.io/RxJava/javadoc/rx/Single.Transformer.html)创建类似的内容

static <T> SingleTransformer<T, T> subscribeAndFinalTransformer() {
        return new SingleTransformer<T, T>() {
            @Override
            public SingleSource<T> apply(Single<T> upstream) {
                return upstream.doOnSubscribe(disposable -> {
                    // Your doOnSubscribe Block
                }).doFinally(() -> {
                    // Your doFinally Block
                });
            }
        };
    }


可以使用Transformer方法为所有Single附加可重复使用的compose

authRepository.login(userName, password).compose(subscribeAndFinalTransformer())
.subscribe()

authRepository.anotherApi().compose(subscribeAndFinalTransformer()).subscribe()


如果您使用的是ObservableCompletable,则应使用等效的Transformer代替SingleTransformer

编辑:

如果您只想对某些调用重用某些操作,则上述方法很方便。

如果要将操作附加到所有API调用,则可以创建Retrofit CallAdapter

class RxStreamAdapter implements CallAdapter {

    private final Class rawType;
    private final CallAdapter<Object, Object> nextAdapter;
    private final Type returnType;

    RxStreamAdapter(Class rawType,
                    Type returnType,
                    CallAdapter nextAdapter) {
        this.rawType = rawType;
        this.returnType = returnType;
        this.nextAdapter = nextAdapter;
    }

    @Override
    public Type responseType() {
        return nextAdapter.responseType();
    }

    @Override
    public Object adapt(Call call) {
        if (rawType == Single.class) {
            return ((Single) nextAdapter.adapt(call))
                    .doOnSubscribe(getDoOnSubscribe())
                    .doFinally(getDoFinally());
        } else if (returnType == Completable.class) {
            return ((Completable) nextAdapter.adapt(call))
                    .doOnSubscribe(getDoOnSubscribe())
                    .doFinally(getDoFinally());
        } else {
            // Observable
            return ((Observable<Object>) nextAdapter.adapt(call))
                    .doOnSubscribe(getDoOnSubscribe())
                    .doFinally(getDoFinally());
        }
    }

    @NotNull
    private Consumer<Disposable> getDoOnSubscribe() {
        return disposable -> {

        };
    }

    @NotNull
    private Action getDoFinally() {
        return () -> {

        };
    }
}


然后在创建Retrofit对象时将其添加(在RxJava2CallAdapterFactory之前)

RetrofitApi retrofitApi = new Retrofit
                .Builder()
                .addCallAdapterFactory(new CallAdapter.Factory() {
                    @Override
                    public CallAdapter<?, ?> get(Type returnType, Annotation[] annotations, Retrofit retrofit) {
                        CallAdapter<?, ?> nextAdapter = retrofit.nextCallAdapter(this, returnType, annotations);
                        Class<?> rawType = getRawType(returnType);
                        if (rawType == Single.class || rawType == Observable.class || rawType == Completable.class) {
                            return new RxStreamAdapter(getRawType(returnType), returnType, nextAdapter);
                        } else {
                            return nextAdapter;
                        }
                    }
                })
                .addCallAdapterFactory(RxJava2CallAdapterFactory.create())
                .build()


您也可以使用RxJavaPlugins设置挂钩。但是您无法区分黑白普通流和翻新流。

希望能帮助到你!

关于java - 如何不在RxJava中重复相同的操作?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/53388850/

10-14 17:18