以下是我目前正在做的事情:
modelbuilder.entity().property(e=>e.name).isRequired();
modelbuilder.entity().property(e=>e.upc).isRequired();
modelbuilder.entity().property(e=>e.price).isRequired();
modelbuilder.entity().property(e=>e.description).isRequired();
我想做的是:
ModelBuilder.Entity()
.property(e=>e.name).isRequired()
.property(e=>e.upc).isRequired()
.property(e=>e.price).isRequired()
.property(e=>e.description).isRequired()
不过,后者不起作用。是否有其他方法不必每次都重复modelbuilder.entity()?
以下是目前最简单的选择:
var e=modelbuilder.entity();
e.property(e=>e.name).isRequired();
e.属性(e=>e.upc).isRequired();
e.property(e=>e.price).isRequired();
e.property(e=>e.description).isRequired();
最佳答案
这与所有现有的DbMultuBu建德扩展方法兼容,因为它只是在上面添加了一个FLUENT层,但是它确实带有一些语法开销。不完全是你所要求的,但不涉及与支持代码混在一起。还没有完全测试过,但是如果您熟悉语法,它应该可以工作:
// First option - like this better because it has less cruft than multiple Has invocations
var modelBuilder = new DbModelBuilder();
var modelConfiguration = new ModelConfigurator(modelBuilder);
modelConfiguration.Entity<Product>().Has(e => {
e.Property(en => en.Name).IsRequired();
e.Property(en => en.UPC).IsRequired();
e.Property(en => en.Price).IsRequired();
e.Property(en => en.Description).IsRequired();}
);
或者
var modelBuilder = new DbModelBuilder();
var modelConfiguration = new ModelConfigurator(modelBuilder);
modelConfiguration.Entity<Product>().Has(e => e.Property(en => en.Name).IsRequired())
.Has(e => e.Property(en => en.UPC).IsRequired())
.Has(e => e.Property(en => en.Price).IsRequired())
.Has(e => e.Property(en => en.Description).IsRequired());
// continue configuring properties, and creating methods on ModelConfigurator as needed
支持代码:
public class Product{
public string Name {get;set;}
public double Price {get;set;}
public string UPC {get;set;}
public string Description {get;set;}
}
public class ModelConfigurator{
public DbModelBuilder ModelBuilder{get;set;}
public ModelConfigurator(DbModelBuilder modelBuilder){
ModelBuilder = modelBuilder;
}
public EntityConfigurator<TEntity> Entity<TEntity>() where TEntity : class {
var entity = ModelBuilder.Entity<TEntity>();
return new EntityConfigurator<TEntity>(entity);
}
}
public class EntityConfigurator<TEntity> where TEntity : class{
public EntityTypeConfiguration<TEntity> EntityTypeConfiguration {get;set;}
public EntityConfigurator(EntityTypeConfiguration<TEntity> entityTypeConfiguration){
EntityTypeConfiguration = entityTypeConfiguration;
}
public EntityConfigurator<TEntity> Has(Action<EntityTypeConfiguration<TEntity>> a){
a(this.EntityTypeConfiguration);
return this;
}
}