我正在尝试输出嵌套关系,其中
猫多(腿)
Leg.belongsTo(cat)
Leg.hasOne(爪子)
pas.hasMany(腿)
这是我的猫模型:
module.exports = (sequelize, DataTypes) => {
const Cat = sequelize.define('Cat', {
userId: {
type: DataTypes.STRING,
},
}, {});
Cat.associate = function (models) {
Cat.hasMany(models.Leg, {
foreignKey: 'catId',
as: 'legs',
});
};
return Cat;
};
我的腿模型:
module.exports = (sequelize, DataTypes) => {
const Leg = sequelize.define('Leg', {
originalValue: DataTypes.JSON,
newValue: DataTypes.JSON,
legId: DataTypes.INTEGER,
objectId: DataTypes.INTEGER,
pawId: DataTypes.INTEGER,
}, {});
Leg.associate = function (models) {
Leg.belongsTo(models.Cat, {
foreignKey: 'LegId',
onDelete: 'CASCADE',
});
Leg.hasOne(models.Paw, {
foreignKey: 'pawId',
});
};
return Leg;
};
这是我的爪子模型
module.exports = (sequelize, DataTypes) => {
const Paw = sequelize.define('Paw', {
pawType: DataTypes.STRING,
}, {});
Paw.associate = function (models) {
Paw.hasMany(models.Leg, {
foreignKey: 'pawId',
as: 'paws',
});
};
return Paw;
};
目前,当我查询Cat表时,我的代码正在输出此代码
[
{
"id": 1,
"userId": "2wdfs",
"createdAt": "2018-04-14T20:12:47.112Z",
"updatedAt": "2018-04-14T20:12:47.112Z",
"legs": [
{
"id": 1,
"catId": 1,
"pawId": 1,
"createdAt": "2018-04-14T20:12:54.500Z",
"updatedAt": "2018-04-14T20:12:54.500Z"
}
]
}
]
但是,当列出cat表中的所有内容时,我希望paws表中的pawType也存在。与此类似:
[
{
"id": 1,
"userId": "2wdfs",
"createdAt": "2018-04-14T20:12:47.112Z",
"updatedAt": "2018-04-14T20:12:47.112Z",
"legs": [
{
"id": 1,
"catId": 1,
"paws" : [
{
"id": 1,
"pawType": "cute"
}
]
"createdAt": "2018-04-14T20:12:54.500Z",
"updatedAt": "2018-04-14T20:12:54.500Z"
}
]
}
]
此外,这是我用来检索猫的查询。
return Cat.findAll({ include: [{ model: Leg, as: 'legs',include [{model: Paw,}], }], })
这是返回的错误,
{ SequelizeDatabaseError: column legs->Paw.pawId does not exist
{ error: column legs->Paw.pawId does not exist
以及完整的SQL命令
sql: 'SELECT "Cat"."id", "Cat"."userId", "Cat"."createdAt", "Cat"."updatedAt", "legs"."id" AS "legs.id", "legs"."originalValue" AS "legs.originalValue", "legs"."newValue" AS "legs.newValue", "legs"."catId" AS "legs.catId", "legs"."objectId" AS "legs.objectId", "legs"."pawId" AS "legs.pawId", "legs"."createdAt" AS "legs.createdAt", "legs"."updatedAt" AS "legs.updatedAt", "legs->Paw"."id" AS "legs.Paw.id", "legs->Paw"."paw" AS "legs.Paw.paw", "legs->Paw"."pawId" AS "legs.Paw.pawId", "legs->Paw"."createdAt" AS "legs.Paw.createdAt", "legs->Paw"."updatedAt" AS "legs.Paw.updatedAt" FROM "Cats" AS "Cat" LEFT OUTER JOIN "Legs" AS "legs" ON "Cat"."id" = "legs"."catId" LEFT OUTER JOIN "Paws" AS "legs->Paw" ON "legs"."id" = "legs->Paw"."pawId";' },
最佳答案
有很多问题。我将尝试逐步解决它们。
1)建模默认情况下,如果不声明primaryKey
,则sequelize会自动为您添加id
列。因此,legId
不是有用的列。
此外,如果您关联一个模型,则会为您添加foreignKey
引用,因此不应声明pawId
。
因此,Legs.js
应该修改为:
module.exports = (sequelize, DataTypes) => {
var Leg = sequelize.define('Leg', {
originalValue: DataTypes.JSON,
newValue: DataTypes.JSON,
objectId: DataTypes.INTEGER // not entirely sure what this is
})
Leg.associate = function (models) {
// associations
}
return Leg
}
上面给出了
pgAdmin
中的以下列:2)关联
以下关联是没有意义的,应该会导致错误:
Leg.hasOne(Paw)
Paw.hasMany(Leg)
Unhandled rejection Error: Cyclic dependency found. Legs is dependent of itself.
Dependency chain: Legs -> Paws => Legs
每个
Leg
应该具有一个Paw
,因此我建议以下内容:Leg.associate = function (models) {
// Leg.belongsTo(models.Cat)
Leg.hasOne(models.Paw, {
foreignKey: 'pawId',
as: 'paw'
})
}
Paw.associate = function (models) {
Paw.belongsTo(models.Leg, {
as: 'leg' // note this changed to make more sense
foreignKey: 'pawId'
})
}
3)外键
Leg.belongsTo(models.Cat, {
foreignKey: 'catId', // this should match
onDelete: 'CASCADE'
})
Cat.hasMany(models.Leg, {
foreignKey: 'catId', // this should match
as: 'legs'
})
4)渴望加载
当渴望加载嵌套关联时,您必须对其进行
include
编码。您还应该使用与模型关联匹配的as
别名:Cat.findAll({
include: [{
model: Leg,
as: 'legs', // Cat.legs
include: [{
model: Paw,
as: 'paw' // Leg.paw instead of Leg.pawId
}]
}]
})
使用整个设置和上面的查询,我获得:
[
{
"id": 1,
"userId": "1",
"createdAt": "2018-04-15T11:22:59.888Z",
"updatedAt": "2018-04-15T11:22:59.888Z",
"legs": [
{
"id": 1,
"originalValue": null,
"newValue": null,
"objectId": null,
"createdAt": "2018-04-15T11:22:59.901Z",
"updatedAt": "2018-04-15T11:22:59.901Z",
"catId": 1,
"paw": {
"id": 1,
"pawType": null,
"createdAt": "2018-04-15T11:22:59.906Z",
"updatedAt": "2018-04-15T11:22:59.906Z",
"pawId": 1
}
}
]
}
]
额外
因为这显然是一种练习设置,所以可以将
Paw
修改为belongsToMany
关系(也许您用爪子将猫连起来了吗?),如下所示:Paw.associate = function (models) {
Paw.belongsToMany(models.Leg, {
foreignKey: 'pawId',
through: 'PawLegs // a through join table MUST be defined
})
}
这将是实现您最初尝试的正确方法
Leg.hasOne(paw)
paw.hasMany(leg)