ios - iOS:JSONModel:NSInvalidArgumentException

我有这个json数据

{"data": [{"id": 3,"nameAr": "Test","nameEn": "Test","active": 1,
"subCategories": [{"id": 27,"nameAr": "Test",
"nameEn": "Test","active": 0,
"sections": [{"id": 53,"nameAr": "Test",
"nameEn": "Test","active": 0},
{"id": 52,"nameAr": "Test","nameEn": "Test","active": 0
}]}]}],"code": "1001","message": "success"
}

在使用JSONModel https://github.com/icanzilb/JSONModel解析此json时

解析此代码

self.categoriesModels = [CategoryModel arrayOfModelsFromDictionaries: [results objectForKey:@"data"]];

并尝试访问嵌套的json

categoryModel.subCategories

我收到这个错误

  -[CategoryModel子类别]：无法识别的选择器已发送到实例0x17404b910
  2015-05-03 20：38：15.019 AkshefFeen [2268：786267] *由于未捕获的异常'NSInvalidArgumentException'终止了应用程序，原因：'-[CategoryModel subCategories]：无法识别的选择器已发送至实例0x17404b910'
  *首先抛出调用堆栈：
  （0x185fb42d8 0x1977800e4 0x185fbb3a4 0x185fb8154 0x185ebaccc 0x100027608 0x18ab1d474 0x18abd7790 0x18aa78240 0x18a9e86ec 0x185f6c2a4 0x185f69230 0x185f69610 0x18x952d197a 036
  libc ++ abi.dylib：以NSException类型的未捕获异常终止

我的模特儿

1-CategoryModel.h

#import "JSONModel.h"
#import "SubCategoryModel.h"

@protocol CategoryModel
@end

@interface CategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SubCategoryModel>* subCategories;

@end

2-SubCategoryModel.h

@protocol SubCategoryModel
@end

@interface SubCategoryModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;
@property (strong, nonatomic) NSArray<SectionModel,Optional>* subCategories;

@end

3-SectionModel.h

#import "JSONModel.h"

@protocol SectionModel
@end

@interface SectionModel : JSONModel

@property (assign, nonatomic) int id;
@property (strong, nonatomic) NSString* nameAr;
@property (strong, nonatomic) NSString* nameEn;
@property (assign, nonatomic) int active;

@end

为什么会出现此错误，以及如何解决？

最佳答案

@ahmed Shoeib：
可能有两个可能的原因：
1.可能是由于任何JSONModel类中的@synthesize关键字。

这可能是由于父对象和子对象之间的命名相同。

请参考此链接以获取JSONModel中的首选命名约定：Click here

或者，您也可以在此处提出同样的问题，然后获得官方答复或解决方案：Click Here