c++ - 如何编译以下程序？

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已关闭8年。




我正在学习线性代数，并认为我会将一些新发现的知识转换成一个小的C++程序。对于这些数字，我偶然发现了我尝试使用的CLN, a Class Library for Numbers。

LinearEquation.h:

#include <iostream>
#include <cln/real.h>
#include <cln/rational.h>
using namespace std;
using namespace cln;

class LinearEquation{
public:
  // constructor
  LinearEquation(cl_R* coefficients, int numFactors, cl_R constant);

  // copy constructor
  LinearEquation(const LinearEquation& le);

  // assignment constructor
  LinearEquation& operator=(const LinearEquation& rhs);

  // destructor
  ~LinearEquation();

  /*
    isSolution returns true if a provided set of rational numbers is a solution
    to this linear Equation, and false otherwise.

    No error checking is done, thus s and num is expected to match the number
    of items in _coefficients;
  */
  bool isSolution(const cl_R* s, int num);

private:
  int _numFactors;
  cl_R* _coefficients;
  cl_R _constant;
};

LinearEquation.cpp:

#include "LinearEquation.h"

// constructor
LinearEquation::LinearEquation(cl_R* coefficients,
                   int numFactors,
                   cl_R constant){
  _numFactors = numFactors;
  _coefficients = new cl_R[numFactors];
  for(int i=0; i<numFactors; i++){
    _coefficients[i] = coefficients[i];
  }
  _constant = constant;
}

// copy constructor
LinearEquation::LinearEquation(const LinearEquation& obj){
  _numFactors = obj._numFactors;
  _coefficients = new cl_R[_numFactors];
  for(int i=0; i<_numFactors; i++){
    _coefficients[i] = obj._coefficients[i];
  }
  _constant = obj._constant;
}

// assignment constructor
LinearEquation& LinearEquation::operator=(const LinearEquation& le){
  if(this != &le){
    _numFactors = le._numFactors;
    delete [] _coefficients;
    _coefficients = new cl_R[_numFactors];
    for(int i=0; i<_numFactors; i++){
      _coefficients[i] = le._coefficients[i];
    }
    _constant = le._constant;
  }
}

// destructor
LinearEquation::~LinearEquation(){
  delete [] _coefficients;
}

bool LinearEquation::isSolution(const cl_R* s, int num){
  cl_R sum = 0;
  for(int i=0; i<_numFactors; i++){
    sum = sum + (_coefficients[i] * s[i]);
  }
  return sum == _constant;
}

最后是main.cpp

#include <cln/integer.h>
#include <cln/real.h>
#include "LinearEquation.h"
#include <iostream>
using namespace cln;
using namespace std;

int main(){
  int le1NumFactors = 2;
  cl_R* le1Coefficients = new cl_R[le1NumFactors];
  le1Coefficients[0] = 3;
  le1Coefficients[1] = 2;
  cl_R le1Constant = 7;
  LinearEquation le1(le1Coefficients, le1NumFactors, le1Constant);

  int le2NumFactors = 2;
  cl_R* le2Coefficients = new cl_R[le2NumFactors];
  le2Coefficients[0] = -1;
  le2Coefficients[1] = 1;
  cl_R le2Constant = 6;
  LinearEquation le2(le2Coefficients, le2NumFactors, le2Constant);

  cl_R* solution = new cl_R[le2NumFactors];
  solution[0] = -1;
  solution[1] = 5;

  cout << "(-1, 5) is " << (le1.isSolution(solution, 2) ? "" : "not ")
       << "a solution to le1." << endl;
  cout << "(-1, 5) is " << (le2.isSolution(solution, 2) ? "" : "not ")
       << "a solution to le2." << endl;

  delete [] le1Coefficients;
  delete [] le2Coefficients;
  delete [] solution;

  return 0;
}

工作正常，但是



没有。产生以下错误消息:

最佳答案

看起来您没有链接cln库。请尝试以下操作(假设库已正确安装):

g++ main.cpp LinearEquation.o -lcln

请参阅文档以获取有关编译的更多详细信息:
http://www.ginac.de/CLN/cln_11.html#SEC64