ios - 制作专为 4 英寸显示器设计的 iPhone 应用程序与 3.5 英寸兼容

我的应用程序在设计时仅考虑了 4 英寸显示屏。在 3.5 英寸模拟器上运行时，应用程序缺少 0.5 英寸。

那么，我的问题是如何在 Xcode 5 中为不同的屏幕尺寸设置不同的 Storyboard？

我知道在我可以使用以下代码之前:

-(void)initializeStoryBoardBasedOnScreenSize {

if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPhone)
{    // The iOS device = iPhone or iPod Touch


    CGSize iOSDeviceScreenSize = [[UIScreen mainScreen] bounds].size;

    if (iOSDeviceScreenSize.height == 480)
    {   // iPhone 3GS, 4, and 4S and iPod Touch 3rd and 4th generation: 3.5 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone35
        UIStoryboard *Main_iPhone2 = [UIStoryboard storyboardWithName:@"Main_iPhone3" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [Main_iPhone2 instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

    if (iOSDeviceScreenSize.height == 568)
    {   // iPhone 5 and iPod Touch 5th generation: 4 inch screen (diagonally measured)

        // Instantiate a new storyboard object using the storyboard file named Storyboard_iPhone4
        UIStoryboard *Main_iPhone = [UIStoryboard storyboardWithName:@"Main_iPhone" bundle:nil];

        // Instantiate the initial view controller object from the storyboard
        UIViewController *initialViewController = [Main_iPhone instantiateInitialViewController];

        // Instantiate a UIWindow object and initialize it with the screen size of the iOS device
        self.window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

        // Set the initial view controller to be the root view controller of the window object
        self.window.rootViewController  = initialViewController;

        // Set the window object to be the key window and show it
        [self.window makeKeyAndVisible];
    }

} else if ([UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad)

{   // The iOS device = iPad

    UISplitViewController *splitViewController = (UISplitViewController *)self.window.rootViewController;
    UINavigationController *navigationController = [splitViewController.viewControllers lastObject];
    splitViewController.delegate = (id)navigationController.topViewController;

}

}

但是与 Xcode 5 的交易，以及我认为此代码不起作用的原因是项目中的“常规”下有一个部分，该部分将 Storyboard建立为整个特定设备类型的主要 Storyboard。

所以，要么有一种不同的方式来做整个单独的 Storyboard事情，要么我在代码上做错了。该代码已放置在我的应用程序委托(delegate)中，所以不要认为我在那里有任何问题。

最佳答案

在 Xcode 5 - Storyboard 中找到这个控件。一直到左侧的按钮可在整个 Storyboard 中的 3.5 和 4 英寸 View 之间切换。希望这是你所需要的。

关于ios - 制作专为 4 英寸显示器设计的 iPhone 应用程序与 3.5 英寸兼容，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/18889505/