我在控制器中有2种方法:
@RestController("/api/v1/users")
public class UserController {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public List<User> getUserByEmailAndPassword(@RequestParam("email") String email, @RequestParam("password") String password) {
logger.info("Request to get user with email and password: " + email + password);
User user = userService.checkUserByEmailAndPassword(email, password);
return user != null ? Collections.singletonList(user) : Collections.emptyList();
}
@RequestMapping(method = RequestMethod.GET)
public List<UserDto> getUserByEmail(@RequestParam("email") String email) {
logger.info("Request to get user with email: " + email);
UserDto userDto = userService.checkUserEmail(email);
return userDto != null ? Collections.singletonList(userDto) : Collections.emptyList();
}
}
CORS配置:
@Configuration
public class CorsConfig {
@Bean
public FilterRegistrationBean corsFilter() {
UrlBasedCorsConfigurationSource source = new UrlBasedCorsConfigurationSource();
CorsConfiguration config = new CorsConfiguration();
config.setAllowCredentials(true);
config.addAllowedOrigin("*");
config.addAllowedHeader("*");
config.addAllowedMethod("*");
source.registerCorsConfiguration("/**", config);
FilterRegistrationBean bean = new FilterRegistrationBean(new CorsFilter(source));
bean.setOrder(0);
return bean;
}
}
当我将请求发送到:http://localhost:9092/api/v1/users/login?email=art&password=1037006322
我称这种方法为getUserByEmail
怎么可能?
如何解决这个问题?
最佳答案
按照这种方式进行映射。它将根据您的要求进行工作。使用@RequestMapping而不是@RestController映射您的url模式。
@RestController
@RequestMapping("/api/v1/users")
public class UserController {
@RequestMapping(value = "/login", method = RequestMethod.GET)
public List<User> getUserByEmailAndPassword(@RequestParam("email") String email, @RequestParam("password") String password) {
logger.info("Request to get user with email and password: " + email + password);
User user = userService.checkUserByEmailAndPassword(email, password);
return user != null ? Collections.singletonList(user) : Collections.emptyList();
}
@RequestMapping(method = RequestMethod.GET)
public List<UserDto> getUserByEmail(@RequestParam("email") String email) {
logger.info("Request to get user with email: " + email);
UserDto userDto = userService.checkUserEmail(email);
return userDto != null ? Collections.singletonList(userDto) : Collections.emptyList();
}
}
关于java - 请求在 Controller 中获取另一种方法(Spring Boot),我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/49388485/