JavaScript代码:
function showdlgBox()
{
var whiteBox = document.getElementById("white-background");
var dlgbox = document.getElementById("dlgBox");
whiteBox.style.display = "block";
dlgbox.style.display = "block";`enter code here`
var winwidth = window.innerWidth;
var winHighet = window.innerHeight;`enter code here`
dlgbox.style.left = (winwidth / 2) - 480 / 2 + "px";
dlgbox.style.top = "150px";
}
的HTML:
<asp:LinkButton ID="LinkButton1" runat="server" OnClick="LinkButton1_Click">LinkButton</asp:LinkButton>
如何在
linkbutton
上调用此javascript? 最佳答案
说明:
据我了解,
OnClick="LinkButton1_Click"
被链接到后端(服务器端)功能-这就是为什么发生回发的原因。
解:
也许尝试将其取出。或者,使用纯HTML锚标记:
<a id='LinkButton1' href='javascript:void(0)'></a>
祝好运