python - 如何获取Python范围函数中所有数字的总和？

我不知道如何把x（从下面的代码中）加到它自身，得到和，然后除以评级的数量。课堂上给出的例子是4个等级，数字是3、4、1和2。平均评分应该是2.5分，但我似乎做得不对！

number_of_ratings = eval(input("Enter the number of difficulty ratings as a positive integer: "))       # Get number of difficulty ratings
for i in range(number_of_ratings):      #   For each diffuculty rating
    x = eval(input("Enter the difficulty rating as a positive integer: "))      # Get next difficulty rating
average = x/number_of_ratings
print("The average diffuculty rating is: ", average)

最佳答案

您的代码没有添加任何内容，只是在每次迭代中覆盖x。可以使用+=运算符向变量添加内容。另外，不要使用eval：

number_of_ratings = int(input("Enter the number of difficulty ratings as a positive integer: "))
x = 0
for i in range(number_of_ratings):
    x += int(input("Enter the difficulty rating as a positive integer: "))
average = x/number_of_ratings
print("The average diffuculty rating is: ", average)

关于python - 如何获取Python范围函数中所有数字的总和？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/4964286/