java - 在计算1 + 2 + 3 + 4…+ n时需要帮助吗？

因此，我被分配编写一个程序，该程序询问一个数字(n)，然后进行如下加法运算:1 + 2 + 3 + 4 ... + n并输出加法运算

虽然我不断得到错误的数字，却无法弄清楚哪里出了问题？

import java.util.Scanner;

public class LukusarjanSumma {

    public static void main(String[] args) {
        Scanner reader = new Scanner(System.in);
        int addition = 0;
        System.out.println("Where to?");
        int n = Integer.valueOf(reader.nextLine());
        while (addition <= n){
            addition += addition;
            addition ++;
        } System.out.println("Total is " + addition);
    }
}

最佳答案

您需要区别对待

总结所有

的additition

值递增索引的counter:1,2,3...n

int addition = 0;
int counter = 0;
System.out.println("Where to?");
int n = Integer.parseInt(reader.nextLine());
while (counter <= n) {
    addition += counter;
    counter++;
}
System.out.println("Total is " + addition);

但是更容易使用for循环，这更合乎逻辑

int n = Integer.parseInt(reader.nextLine());
for (int i = 0; i <= n; i++) {
    addition += i;
}