我收到一个错误,我不知道为什么。我有这个项目:

java - 找不到Java Apache Tomcat所需的资源-LMLPHP

当我执行registro.html时,效果很好:

java - 找不到Java Apache Tomcat所需的资源-LMLPHP

但是当我在代码中提交帖子时,我认为它没有到达Registro.java

java - 找不到Java Apache Tomcat所需的资源-LMLPHP

registro.html中的代码是:

<!DOCTYPE html>
<html>
    <head>
        <meta charset="ISO-8859-1">
        <title>Registro</title>
    </head>
    <body>
        <form action="http://localhost:8080/Ejer2/Registro.java" method="POST">
            <input type=hidden name=registro value=resultadoRegistro>
            <BR><BR>Username: <input type=text name=user>
            <BR><BR>Password: <input type=password name=pass>
            <BR><BR><input type=submit value="Enviar"><input type=reset>
        </form>
    </body>
</html>


在Registro.java中:

    package Ejer2;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import javax.servlet.http.HttpSession;
import javax.servlet.*;



@SuppressWarnings("deprecation")
public class Registro extends HttpServlet implements SingleThreadModel{
    private static final long serialVersionUID = 1L;



    public Registro() {
        super();

    }



    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {


    }


    protected void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
        HttpSession session=req.getSession(true);
        Usuario miuser=(Usuario)session.getValue(session.getId());
        if(miuser==null){
            miuser=new Usuario(req.getParameter("user"),req.getParameter("password"));
            session.putValue(session.getId(),miuser);
        }
        res.setContentType("text/html");

        String user=req.getParameter("user");
        //String pass = req.getParameter("pass");

        PrintWriter toClient = res.getWriter();
        toClient.println("<html>");
        toClient.println("<title>REGISTRO REALIZADO</title>");
        toClient.println("Usuario "+user+" registrado con exito");
        toClient.println("</html>");

        toClient.close();
    }

}


问题是什么?

最佳答案

您不能直接在html Registro.java内部使用或调用action,而是需要映射Registro servlet类的url模式,如下所示:

@WebServlet(urlPatterns="/Registro")
public class Registro extends HttpServlet implements SingleThreadModel{
   //Add your code here
}


现在,将上面配置的urlPattern用作action中的registro.html,如下所示:

<form action="/Registro" method="POST">


另外,另一个要点是,对于servlet类,通常不需要SingleThreadModel(因为所有请求都将使用同一servlet实例进行处理),但是如果您故意使用SingleThreadModel,则可以离开照原样。

07-26 09:30