我正在尝试使用PHP将CSV文件转换为JSON。
这是我的代码
<?php
date_default_timezone_set('UTC');
$today = date("n_j"); // Today is 1/23/2015 -> $today = 1_23
$file_name = $today.'.CSV'; // My file name is 1_23.csv
$file_path = 'C:\\Users\\bheng\\Desktop\\qb\\'.$file_name;
$file_handle = fopen($file_path, "r");
$result = array();
if ($file_handle !== FALSE) {
$column_headers = fgetcsv($file_handle);
foreach($column_headers as $header) {
$result[$header] = array();
}
while (($data = fgetcsv($file_handle)) !== FALSE) {
$i = 0;
foreach($result as &$column) {
$column[] = $data[$i++];
}
}
fclose($file_handle);
}
// print_r($result); // I see all data(s) except the header
$json = json_encode($result);
echo $json;
?>
然后我
json_encode($result);并尝试显示它，但是屏幕上什么都没有显示。我所看到的只是空白屏幕和0错误消息。我做错什么了吗？有人能帮我吗 ？
Array (
[Inventory] => Array (
[0] => bs-0468R(20ug)
[1] => bs-1338R(1ml)
[2] => bs-1557G(no bsa)
[3] => bs-3295R(no BSA)
[4] => bs-0730R-Cy5"
[5] => bs-3889R-PE-Cy7"
[6] => 11033R
[7] => 1554R-A647
[8] => 4667
[9] => ABIN731018
[10] => Anti-DBNL protein
.... more ....
最佳答案
尝试这样:
$file="1_23.csv";
$csv= file_get_contents($file);
$array = array_map("str_getcsv", explode("\n", $csv));
$json = json_encode($array);
print_r($json);