c++ - 我如何让一个类函数接受另一个对象？ (C++)

我希望Account类保留一个人的名字，姓氏及其余额

Produce类包含有关水果或蔬菜类型的信息

我希望Account类中的SellProd函数接受一个Produce对象，以便它可以将该Produce的价格添加到该人的余额中。
到目前为止，该函数给我一个错误，提示“未知类型名称'Produce'

任何提示，使它工作？

#include <iostream>
#include <string>

using namespace std;

class Account
{
    friend class Produce;
private:
    double funds;
    string ownerfirst, ownerlast;
    void addToFunds(double p) { funds += p;};
public:
    Account( string first, string last) { ownerfirst = first; ownerlast = last; funds = 0;};
    void printAccount()
    {
        cout<<"Account Holder: "<<ownerfirst<<" "<<ownerlast<<endl;
        cout<<"Account Balance: "<<funds<<endl;
    };
    void sellProd(Produce a)
    {
        cout<<"Selling: "<<kind<<" | Classified as: "<<type<<endl;
        cout<<"Current Balance: "<<funds<<endl<<"Sell price: "<<price<<endl;
        addToFunds(price);
        cout<<"New Balance: "<<funds<<endl;
    };

};
class Produce
{
private:
    string kind;
    string type; //fruit or vegetable
    double price;
public:
    void printProd()
    {
        cout<<"Type of "<<type<<": "<<kind<<endl;
        cout<<"Selling for: "<<price<<"$"<<endl;
    };
    Produce( string k, string t, double p) { kind = k; type = t; price = p;};
};

int main()
{
    Account myAccount("John", "Doe");
    myAccount.printAccount();
    Produce prod1("Tomato", "Fruit", 2.99);
    Produce prod2("Apple", "Fruit", 0.99);
    Produce prod3("Carrots", "Vegetable", 1.49);
    Produce prod4("Potato", "Vegetable", 1.29);

    prod1.printProd();
    myAccount.printAccount();

}

最佳答案

Produce是在Account之后定义的，因此，当编译器看到函数的定义时，它还没有看到Produce是什么。只需切换定义，使Produce在Account之前。