我需要将Hashmap绑定到MutableTreeNode，以便可以在JTree中显示它。
我有以下代码：
static Map<String, String> form = new LinkedHashMap<String,String>();
我想这就是实现
MutableTreeNode的方式。我只是不知道现在该如何进行操作以使“表单”的键出现在MutableTreeNode中。public class MyNode implements MutableTreeNode {
@Override
public Enumeration children() {
// TODO Auto-generated method stub
return null;
}
@Override
public boolean getAllowsChildren() {
// TODO Auto-generated method stub
return false;
}
@Override
public TreeNode getChildAt(int childIndex) {
// TODO Auto-generated method stub
return null;
}
@Override
public int getChildCount() {
// TODO Auto-generated method stub
return 0;
}
@Override
public int getIndex(TreeNode node) {
// TODO Auto-generated method stub
return 0;
}
@Override
public TreeNode getParent() {
// TODO Auto-generated method stub
return null;
}
@Override
public boolean isLeaf() {
// TODO Auto-generated method stub
return false;
}
@Override
public void insert(MutableTreeNode arg0, int arg1) {
// TODO Auto-generated method stub
}
@Override
public void remove(int arg0) {
// TODO Auto-generated method stub
}
@Override
public void remove(MutableTreeNode arg0) {
// TODO Auto-generated method stub
}
@Override
public void removeFromParent() {
// TODO Auto-generated method stub
}
@Override
public void setParent(MutableTreeNode arg0) {
// TODO Auto-generated method stub
}
@Override
public void setUserObject(Object arg0) {
// TODO Auto-generated method stub
}
MutableTreeNode正确显示正确的Key值后，我希望能够执行以下操作：final JTree tree = new JTree();
final DefaultMutableTreeNode CustomNode = new DefaultMutableTreeNode("Custom");
DefaultTreeModel tm = new DefaultTreeModel(CustomNode);
tree.setModel(tm);
for (String str : form.keySet())
{
MyNode nod = new MyNode(str);
CustomNode.add(node);
}
tm.reload();
最佳答案
您可能需要TreeModel接口的自定义实现。如How to Use Trees: Creating a Data Model中所述，
TreeModel接口接受任何类型的对象作为树节点。它不需要节点由DefaultMutableTreeNode对象表示，甚至不需要节点实现TreeNode接口。
尽管您的Map<String, String>并非本质上是分层的，但您可能会从GenealogyModel，引用为here或FileTreeModel引用为here和here的想法。