我已经分析好了。但现在我很难得到价值观
我需要的。我可以得到元素和属性。但无法获得这些值。
我想得到这个xml中frame的值是20。
/* track the current level in the xml tree */
static int depth = 0;
/* first when start element is encountered */
void start_element(void *data, const char *element, const char **attribute)
{
int i;
for(i = 0; i < depth; i++)
{
printf(" ");
}
printf("%s", element);
for(i = 0; attribute[i]; i += 2)
{
printf(" %s= '%s'", attribute[i], attribute[i + 1]);
}
printf("\n");
depth++;
}
/* decrement the current level of the tree */
void end_element(void *data, const char *el)
{
depth--;
}
int parse_xml(char *buff, size_t buff_size)
{
FILE *fp;
fp = fopen("start_indication.xml", "r");
if(fp == NULL)
{
printf("Failed to open file\n");
return 1;
}
XML_Parser parser = XML_ParserCreate(NULL);
int done;
XML_SetElementHandler(parser, start_element, end_element);
memset(buff, 0, buff_size);
printf("strlen(buff) before parsing: %d\n", strlen(buff));
size_t file_size = 0;
file_size = fread(buff, sizeof(char), buff_size, fp);
/* parse the xml */
if(XML_Parse(parser, buff, strlen(buff), XML_TRUE) == XML_STATUS_ERROR)
{
printf("Error: %s\n", XML_ErrorString(XML_GetErrorCode(parser)));
}
fclose(fp);
XML_ParserFree(parser);
return 0;
}
<data>
<header length="4">
<item name="time" type="time">16</item>
<item name="ref" type="string">3843747</item>
<item name="port" type="int16">0</item>
<item name="frame" type="int16">20</item>
</header>
</data>
Output from parsing
Element: data
Element: header length= '4'
Element: item name= 'time' type= 'time'
Element: item name= 'ref' type= 'string'
Element: item name= 'port' type= 'int16'
Element: item name= 'frame' type= 'int16'
最佳答案
对于外籍人士来说,这是相当困难的。当您只对结构感兴趣而不是对元素的内容感兴趣时,expat会更好。为什么不改用libxml?您使用基于偶数的解析器(如expat)而不是基于树的解析器的原因是什么?
无论如何,方法是设置字符数据处理程序。下面是一个基于代码的示例:
#include <expat.h>
#include <stdio.h>
#include <string.h>
#define BUFFER_SIZE 100000
/* track the current level in the xml tree */
static int depth = 0;
static char *last_content;
/* first when start element is encountered */
void
start_element(void *data, const char *element, const char **attribute)
{
int i;
for (i = 0; i < depth; i++) {
printf(" ");
}
printf("%s", element);
for (i = 0; attribute[i]; i += 2) {
printf(" %s= '%s'", attribute[i], attribute[i + 1]);
}
printf("\n");
depth++;
}
/* decrement the current level of the tree */
void
end_element(void *data, const char *el)
{
int i;
for (i = 0; i < depth; i++) {
printf(" ");
}
printf("Content of element %s was \"%s\"\n", el, last_content);
depth--;
}
void
handle_data(void *data, const char *content, int length)
{
char *tmp = malloc(length);
strncpy(tmp, content, length);
tmp[length] = '\0';
data = (void *) tmp;
last_content = tmp; /* TODO: concatenate the text nodes? */
}
int
parse_xml(char *buff, size_t buff_size)
{
FILE *fp;
fp = fopen("start_indication.xml", "r");
if (fp == NULL) {
printf("Failed to open file\n");
return 1;
}
XML_Parser parser = XML_ParserCreate(NULL);
XML_SetElementHandler(parser, start_element, end_element);
XML_SetCharacterDataHandler(parser, handle_data);
memset(buff, 0, buff_size);
printf("strlen(buff) before parsing: %d\n", strlen(buff));
size_t file_size = 0;
file_size = fread(buff, sizeof(char), buff_size, fp);
/* parse the xml */
if (XML_Parse(parser, buff, strlen(buff), XML_TRUE) == XML_STATUS_ERROR) {
printf("Error: %s\n", XML_ErrorString(XML_GetErrorCode(parser)));
}
fclose(fp);
XML_ParserFree(parser);
return 0;
}
int
main(int argc, char **argv)
{
int result;
char buffer[BUFFER_SIZE];
result = parse_xml(buffer, BUFFER_SIZE);
printf("Result is %i\n", result);
return 0;
}
关于c - 使用xml解析器Expat获取xml数据,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/609376/