我已经分析好了。但现在我很难得到价值观
我需要的。我可以得到元素和属性。但无法获得这些值。
我想得到这个xml中frame的值是20。

/* track the current level in the xml tree */
static int depth = 0;
/* first when start element is encountered */
void start_element(void *data, const char *element, const char **attribute)
{
int i;

for(i = 0; i < depth; i++)
{
    printf(" ");
}

printf("%s", element);

for(i = 0; attribute[i]; i += 2)
{
    printf(" %s= '%s'", attribute[i], attribute[i + 1]);
}

printf("\n");
depth++;
}

/* decrement the current level of the tree */
void end_element(void *data, const char *el)
{
depth--;
}
int parse_xml(char *buff, size_t buff_size)
{
    FILE *fp;
    fp = fopen("start_indication.xml", "r");
    if(fp == NULL)
    {
    printf("Failed to open file\n");
    return 1;
    }

    XML_Parser parser = XML_ParserCreate(NULL);
    int done;
    XML_SetElementHandler(parser, start_element, end_element);

    memset(buff, 0, buff_size);
    printf("strlen(buff) before parsing: %d\n", strlen(buff));

    size_t file_size = 0;
    file_size = fread(buff, sizeof(char), buff_size, fp);

    /* parse the xml */
    if(XML_Parse(parser, buff, strlen(buff), XML_TRUE) == XML_STATUS_ERROR)
    {
        printf("Error: %s\n", XML_ErrorString(XML_GetErrorCode(parser)));
    }

    fclose(fp);
    XML_ParserFree(parser);

    return 0;
}



<data>
    <header length="4">
            <item name="time" type="time">16</item>
            <item name="ref" type="string">3843747</item>
            <item name="port" type="int16">0</item>
            <item name="frame" type="int16">20</item>
    </header>
</data>

Output from parsing


Element: data
Element: header length= '4'
Element: item name= 'time' type= 'time'
Element: item name= 'ref' type= 'string'
Element: item name= 'port' type= 'int16'
Element: item name= 'frame' type= 'int16'

最佳答案

对于外籍人士来说,这是相当困难的。当您只对结构感兴趣而不是对元素的内容感兴趣时,expat会更好。为什么不改用libxml?您使用基于偶数的解析器(如expat)而不是基于树的解析器的原因是什么?
无论如何,方法是设置字符数据处理程序。下面是一个基于代码的示例:

#include <expat.h>
#include <stdio.h>
#include <string.h>

#define BUFFER_SIZE 100000

/* track the current level in the xml tree */
static int      depth = 0;

static char    *last_content;

/* first when start element is encountered */
void
start_element(void *data, const char *element, const char **attribute)
{
    int             i;

    for (i = 0; i < depth; i++) {
        printf(" ");
    }

    printf("%s", element);

    for (i = 0; attribute[i]; i += 2) {
        printf(" %s= '%s'", attribute[i], attribute[i + 1]);
    }

    printf("\n");
    depth++;
}

/* decrement the current level of the tree */
void
end_element(void *data, const char *el)
{
    int             i;
    for (i = 0; i < depth; i++) {
        printf(" ");
    }
    printf("Content of element %s was \"%s\"\n", el, last_content);
    depth--;
}

void
handle_data(void *data, const char *content, int length)
{
    char           *tmp = malloc(length);
    strncpy(tmp, content, length);
    tmp[length] = '\0';
    data = (void *) tmp;
    last_content = tmp;         /* TODO: concatenate the text nodes? */
}

int
parse_xml(char *buff, size_t buff_size)
{
    FILE           *fp;
    fp = fopen("start_indication.xml", "r");
    if (fp == NULL) {
        printf("Failed to open file\n");
        return 1;
    }

    XML_Parser      parser = XML_ParserCreate(NULL);
    XML_SetElementHandler(parser, start_element, end_element);
    XML_SetCharacterDataHandler(parser, handle_data);

    memset(buff, 0, buff_size);
    printf("strlen(buff) before parsing: %d\n", strlen(buff));

    size_t          file_size = 0;
    file_size = fread(buff, sizeof(char), buff_size, fp);

    /* parse the xml */
    if (XML_Parse(parser, buff, strlen(buff), XML_TRUE) == XML_STATUS_ERROR) {
        printf("Error: %s\n", XML_ErrorString(XML_GetErrorCode(parser)));
    }

    fclose(fp);
    XML_ParserFree(parser);

    return 0;
}

int
main(int argc, char **argv)
{
    int             result;
    char            buffer[BUFFER_SIZE];
    result = parse_xml(buffer, BUFFER_SIZE);
    printf("Result is %i\n", result);
    return 0;
}

关于c - 使用xml解析器Expat获取xml数据,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/609376/

10-12 02:13