java - 如何在for循环中找到第二大数字

public static void main(String[] args) {
    int num;
    int large;
    int small;
    int secondLarge;

    Scanner scan = new Scanner(System.in);
    System.out.print("Input a number: ");
    num = scan.nextInt();
    large = num;
    small = num;
    secondLarge = num;

    for (int x = 9; x > 0; x--) {
        System.out.print("Enter " + x + " more number: ");
        num = scan.nextInt();

        if (num > large) {
            large = num;

        }
        if (num > secondLarge) {
            secondLarge = num;
        }

        if (secondLarge > large) {
            large = secondLarge;

        }
        if (num < small) {
            small = num;

        }

    } System.out.println( large + " is the largest number, " + secondLarge + " is the second largest number and " + small + " is the smallest number!");
}

因此，我试图输出最大，第二大和最小的数字。我能够得到最小和最大的东西，但是不知道从哪里开始获得第二大的东西。我以为这会工作，但它输出的东西一样大。我目前不打算使用数组，因为这是家庭作业。请不要告诉我确切的答案，但是一些帮助和提示会很棒！

最佳答案

初始化变量如

int largest=0;
int secondlargest=0;
int smallest=Integer.MAX_VALUE;

条件应该像

if(number>=largest){
    secondlargest=largest;
    largest=number;
}else if(number>secondlargest){
    secondlargest=number;
}
if(number<smallest){
    smallest=number;
}