我对问题的回答有效,包含在我的回答中的Pedrag的评论也有效
我正在进行http请求调用,并且不显示页面,直到http响应返回(请求调用为getRoadmaps)。我有一个称为“正在加载”的redux状态,以确定响应是否回来了?关于如何在我的代码中实现的任何见解?我的其他还原状态是路线图,其中包含一个也称为路线图的对象(对不起,抱歉)。
附言我看到了说做的一些答案(伪代码):如果未加载,则显示加载屏幕,否则加载渲染中的普通屏幕。但是我的问题并不存在于渲染中,而是存在于我做的componentWillMount()中
this.props.getRoadmaps()
然后三行我在哪里
console.log(this.displayRoadmap[0].roadmap[0])
如果getRoadmaps()完成,应该可以成功记录路线图,好像调用了getRoadmaps(),但随后程序继续运行而没有完全完成getRoadmaps(),这导致我的displayRoadmap无法定义。这也会导致一些怪异的现象,例如,如果我从一个屏幕转到该组件,它将始终有效,但是如果刷新页面,它将无法正常工作
import React, { Component } from "react";
import Tree from "./Tree";
import TreeSidebar from "./TreeSidebar";
import { withRouter } from "react-router-dom";
import { connect } from "react-redux";
import { getRoadmaps } from "../actions/roadmapAction";
class OneRoadmap extends Component {
constructor(props) {
super(props);
this.state = {
loading: this.props.roadmap.loading,
roadmapName: "click a white circle to show more!",
roadmapImg:
"https://cdn3.iconfinder.com/data/icons/harmonicons-06/64/plus-circle-512.png",
roadmapDetail: [{ text: "Click on something" }, { text: "hi" }],
treeData: //deleted,just the default big json object
};
}
componentWillMount() {
this.props.getRoadmaps();
var location1 = this.props.location.pathname;
var n = location1.slice(9);
var current_roadmaps = this.props.roadmap.roadmaps;
this.displayRoadmap = current_roadmaps.filter(
eachRoadmap => eachRoadmap._id == n
);
// now we have a roadmap
console.log(this.displayRoadmap[0].roadmap[0]);
this.setState({ treeData: this.displayRoadmap[0].roadmap[0] });
console.log("is good");
console.log(this.props.loading);
}
componentDidMount() {}
handle_on_click_change = d => {
this.setState({ roadmapName: d.data.name });
this.setState({ roadmapImg: d.data.img });
if (d.data.details == undefined) {
this.setState({
roadmapDetail: [{ text: "The author did not put anything here" }]
});
} else {
this.setState({ roadmapDetail: d.data.details });
}
};
render() {
return (
<div>
{console.log(this.state.loading)}
<ul>
<li styles={{ float: "left" }}>
<div>
{console.log(this.state.treeData)}
<Tree
on_click_change={this.handle_on_click_change}
roadmapData={this.state.treeData}
/>
</div>
</li>
<li styles={{ float: "right" }}>
<div>
<TreeSidebar
displayName={this.state.roadmapName}
displayImg={this.state.roadmapImg}
displayDetail={this.state.roadmapDetail}
/>
</div>
</li>
</ul>
</div>
);
}
}
const mapStateToProps = state => ({
roadmap: state.roadmap
});
export default connect(
mapStateToProps,
{ getRoadmaps }
)(OneRoadmap);
最佳答案
就我个人而言,我是如何使用CSS样式的,我不知道这是否是执行此操作的最佳方法,但对我有用,我会做类似的事情
this state = {
loaderStyle: 'block',
contentStyle: 'none'
}
componentDidMount() {
If(this.displayRoadmap[0].length > 0) {
this.setsState({loaderStyle: 'none', contentStyle:
'block:
} else /// do something
};
在我的渲染函数中,我将执行此操作
<Loader style={{display: this.state.loaderStyle}}/>
<Content style={{display: this.state.contentStyle}}>.
</Content>