我刚刚开始使用pyaudio
,我写了一个简单的函数来演奏音符。但是,根据我使用的Python版本,注释听起来有所不同:
from __future__ import division
import math
import pyaudio
BITS_PER_BYTE = 8 # for clarity
SAMPLE_BIT_DEPTH = 8 # i.e. each sample is 1 byte
SAMPLES_PER_SECOND = 16000
NOTE_TIME_SECONDS = 1
MIDDLE_C_HZ = 523.3
CYCLES_PER_SECOND = SAMPLES_PER_SECOND / MIDDLE_C_HZ
NUM_SAMPLES = SAMPLES_PER_SECOND * NOTE_TIME_SECONDS
def play_note():
audio = pyaudio.PyAudio()
stream = audio.open(
format=audio.get_format_from_width(SAMPLE_BIT_DEPTH / BITS_PER_BYTE),
channels=1,
rate=SAMPLES_PER_SECOND,
output=True,
)
byte_string = str()
for i in range(NUM_SAMPLES):
# calculate the amplitude for this frame as a float between -1 and 1
frame_amplitude = math.sin(i / (CYCLES_PER_SECOND / math.pi))
# scale the amplitude to an integer between 0 and 255 (inclusive)
scaled_amplitude = int(frame_amplitude * 127 + 128)
# convert amplitude to byte string (ascii value)
byte_string += chr(scaled_amplitude)
stream.write(byte_string)
stream.close()
audio.terminate()
if __name__ == '__main__':
play_note()
在Python
2.7.13
中,我听到正确,清晰的音调。在3.6.2
中,听起来像方波。为什么会这样,我将如何解决(或至少开始调试)呢?
我正在使用portaudio
v10.11.6
在OSX v19.6.0
上。 最佳答案
这是因为当您应该使用str
时,您正在使用byte
。
这对我有用:
byte_array = bytearray() # bytearray instead of str
for i in range(NUM_SAMPLES):
frame_amplitude = math.sin(i / (CYCLES_PER_SECOND / math.pi))
scaled_amplitude = int(frame_amplitude * 127 + 128)
# Note the append here, not +=
byte_array.append(scaled_amplitude)
stream.write(bytes(byte_array))