想法是拥有一个二维数组NxN,其中所有元素(从0到N * N的数字)都位于随机位置。要生成我使用的随机数:
// Creates a set so we avoid repetition of generated numbers
Set<Integer> generatedNumbers = new LinkedHashSet<Integer>();
while (generatedNumbers.size() < numberOfElements){
Integer next = rng.nextInt(numberOfElements) ;
generatedNumbers.add(next);
}
现在,我需要将元素复制到二维数组。基本上是这样的:
for (Integer number: generatedNumbers){
// Here I'd like to have:
// 1st iteration: board[0][0] = number
// 2nd iteration: board[0][1] = number
// ...
// last iteration: board[3][3] = number
}
哪里:
board = new int[boardSize][boardSize];
对于这种特殊情况,boardSize = 4。
顺便说一句,如果有更好的方法可以达到相同目的,但是使用不同的方法,我很乐于阅读。
最佳答案
如果我理解正确,您想将一个集合中的数字随机分配到一个二维数组中。这是一个基于您提供给我们的工作代码,可以完成此工作:
public static Integer[][] getRandomNumbersArray(int base)
{
Random rng = new Random();
int numberOfElements = base * base;
// Let's use a list so we access by index
List<Integer> generatedNumbers = new ArrayList<>();
for (int i = 0; i < numberOfElements; i++)
{
// Generate our random number
Integer next = rng.nextInt(numberOfElements) ;
// Check if the number is already added
if (!generatedNumbers.contains(next)) {
generatedNumbers.add(next);
}
// Number was a duplicate, redo loop cycle
else i--;
}
// Create our board array here
Integer[][] array = new Integer[base][base];
// Index used to access the list
int i1 = 0;
for (int i2 = 0; i2 < base; i2++)
{
// Populate board row
for (int i3 = 0; i3 < base; i3++, i1++) {
array[i2][i3] = generatedNumbers.get(i1);
}
}
return array;
}
public static void main(String[] args)
{
Integer[][] array = getRandomNumbersArray(4);
System.out.println("Here is how our board looks like:");
for (int i = 0; i < array.length; i++) {
System.out.println(Arrays.toString(array[i]));
}
}
输出量
Here is how our board looks like:
[8, 7, 11, 3]
[15, 5, 1, 0]
[2, 9, 10, 12]
[13, 4, 6, 14]