我正在使用此方法在此自动机模拟器上从一种状态移至另一种状态：
public void processString (String string){
StringBuilder stepString= new StringBuilder (string);
int actualStateIntIndex;
System.out.println("THE FOUND INITIAL ONE IS "+ theInitialStateIntIndex);
State firstState = allStates.get(theInitialStateIntIndex);
actualState = firstState;
while (stepString.length()>0){
Character characterToProcess = stepString.charAt(0);
stepString.deleteCharAt(0);
State nextState;
nextState = ((State)actualState.get(characterToProcess)); // pasa al siguiente State
actualState = nextState;
actualStateIntIndex=allStates.indexOf(actualState);
System.out.println("the actual state for " + stepString + " is " + actualStateIntIndex);
if ((actualState.isFinal==true) && (stepString.length()==0))
{
System.out.println("THE STRING " + string + " IS ACCEPTED AT STATE " + actualStateIntIndex );
}
else if (stepString.length()==0 && (actualState.isFinal==false)){
System.out.println("THE STRING " + string + " IS REJECTED AT STATE " + actualStateIntIndex);
}
}
}
这里：
State nextState;
nextState = ((State)actualState.get(characterToProcess));
我可能做错了什么，但我不明白。
尽管StringBuilder已被正确处理，但自动机始终停留在状态0，为什么？
这是完整的代码：
package afd;
import java.io.*;
import java.util.*;
/**
*
* @author Administrator
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws IOException {
// TODO code application logic here
FileReader fr = new FileReader("E://Documents and Settings//Administrator//My Documents//NetBeansProjects//AFD//src//afd//dfa.in");
BufferedReader br = new BufferedReader(fr);
String firstLine= br.readLine();
String [] firstLineSplitted = firstLine.split(" ");
/*debug*/
//System.out.println("firstLine is " + firstLine);
int numberOfTestCases = Integer.parseInt(firstLine);
for (int indexOfTestCases =0; indexOfTestCases < numberOfTestCases; indexOfTestCases++ ){
int aux;
System.out.println("Case Number " + (aux = indexOfTestCases+1));
String caseStartLine = br.readLine();
/*debug*/
//System.out.println("caseStarLine is " + caseStartLine);
String [] caseStartLineSplitted = caseStartLine.split(" ");
int numberOfStates;
int numberOfAlphabetSymbols;
int numberOfFinalStates;
numberOfStates = Integer.parseInt(caseStartLineSplitted[0]);
numberOfAlphabetSymbols = Integer.parseInt(caseStartLineSplitted[1]);
numberOfFinalStates = Integer.parseInt(caseStartLineSplitted[2]);
Automaton automaton = new Automaton();
automaton.setAllStates(numberOfStates);
// automaton.size = numberOfStates;
// automaton.numberOfAlphabetSymbols = numberOfAlphabetSymbols;
// automaton.numberOfFinalStates = numberOfFinalStates;
//Automaton a = new Automaton(numberOfStates);
String alphabetLine = br.readLine();
System.out.println("alphabetLine is " + alphabetLine);
automaton.setAlphabet (alphabetLine);
// automaton.alphabetSymbols =new StringBuffer(alphabetLine);
for (int indexOfStates = 0; indexOfStates < numberOfStates; indexOfStates++){
String transitionsLine = br.readLine();
/*debug*/
System.out.println("for the state " + indexOfStates + " transitionsLine is " + transitionsLine);
automaton.setTransitions(indexOfStates,transitionsLine);
/*String [] ijLineSplitted = ijLine.split(" ");
int i = Integer.parseInt(ijLineSplitted[0]);
int j = Integer.parseInt(ijLineSplitted[1]);
*/
}
String finalStatesLine = br.readLine();
/*debug*/
System.out.println("finalStatesLine is " + finalStatesLine);
String finalStatesLineSplitted [] = finalStatesLine.split(" ");
automaton.markFinalStates(finalStatesLineSplitted);
String initialStateAndNumberOfStringsLine = br.readLine();
/*debug*/
//System.out.println("initialStateAndNumberOfStringsLine is " +initialStateAndNumberOfStringsLine);
String [] splittedInitialStateLine = initialStateAndNumberOfStringsLine.split(" ");
int initialState = Integer.parseInt(splittedInitialStateLine[0]);
int numberOfStrings = Integer.parseInt(splittedInitialStateLine[1]);
automaton.markInitialState(initialState);
for (int stringIndex =0; stringIndex<numberOfStrings; stringIndex++){
String stringToProcess = br.readLine();
/*debug*/
System.out.println("stringToProcess is " + stringToProcess);
automaton.processString(stringToProcess);
}
}
}
}
class State extends HashMap<Character, State>{
boolean isFinal;
boolean isInitial;
int stateId;
State () {
isInitial=false;
isFinal = false;
}
public boolean equals (Object o){
boolean isEqual = false;
State compare = (State)o;
if ((compare.stateId)==this.stateId)
{
return true;
}
return isEqual;
}
public int hashCode() {
int theHashCode = stateId%7;
return theHashCode;
}
}
class Automaton{
List <State> allStates;
//private List<State> finalStates;
int theInitialStateIntIndex;
State actualState;
char [] alphabet;
Automaton() {
allStates = new ArrayList<State>();
}public void setAllStates (int numberOfStates) {
for (int i =0; i <numberOfStates; i++) {
State newState = new State();
newState.stateId = i;
allStates.add(newState);
}
}
public void setAlphabet (String alphabetLine){
alphabet = alphabetLine.toCharArray();
}
public void markFinalStates (String [] finalStates){
for (int index =0; index<finalStates.length; index++) {
int aFinalStateId = Integer.parseInt(finalStates[index]);
State aFinalState = allStates.get(aFinalStateId);
aFinalState.isFinal = true;
allStates.add(aFinalStateId, aFinalState);
/*DEBUG*/
aFinalState = allStates.get(aFinalStateId);
if ((aFinalState.isFinal)==true)
System.out.println("THE STATE " + aFinalStateId + " IS MARKED AS FINAL");
}
}
public void markInitialState (int initialStateId) {
State theInitialState = allStates.get(initialStateId);
theInitialState.isInitial=true;
allStates.add(initialStateId, theInitialState);
theInitialStateIntIndex = initialStateId;
/*DEBUG*/
System.out.println("THE INITIAL STATE ID IS " + initialStateId);
theInitialState = allStates.get(initialStateId);
if ((theInitialState.isInitial)==true)
System.out.println("THE STATE " + initialStateId + " IS MARKED AS INITIAL");
}
public void setTransitions(int stateId, String transitionsLine){
State theOneToChange = allStates.get(stateId);
String [] statesToReachStringSplitted = transitionsLine.split(" ");
for (int symbolIndex=0; symbolIndex<statesToReachStringSplitted.length;symbolIndex++){
int reachedState= Integer.parseInt(statesToReachStringSplitted[symbolIndex]);
theOneToChange.put(alphabet[symbolIndex],allStates.get(reachedState));
System.out.println("THE STATE " + stateId + " REACHES THE STATE " + reachedState + " WITH THE SYMBOL " + alphabet[symbolIndex]);
}
allStates.add(stateId, theOneToChange);
}
public int findInitialState(){
int index =0;
cycle: for (; index<allStates.size(); index++){
State s = allStates.get(index);
if (s.isInitial==true) {
break cycle;
}
} return index;
}
public void processString (String string)
{
StringBuilder stepString= new StringBuilder (string);
int actualStateIntIndex;
System.out.println("THE FOUND INITIAL ONE IS "+ theInitialStateIntIndex);
State firstState = allStates.get(theInitialStateIntIndex);
actualState = firstState;
while (stepString.length()>0){
Character characterToProcess = stepString.charAt(0);
stepString.deleteCharAt(0);
State nextState;
nextState = ((State)actualState.get(characterToProcess)); // pasa al siguiente State
actualState = nextState;
actualStateIntIndex=allStates.indexOf(actualState);
System.out.println("the actual state for " + stepString + " is " + actualStateIntIndex);
if ((actualState.isFinal==true) && (stepString.length()==0))
{
System.out.println("THE STRING " + string + " IS ACCEPTED AT STATE " + actualStateIntIndex );
}
else if (stepString.length()==0 && (actualState.isFinal==false)){
System.out.println("THE STRING " + string + " IS REJECTED AT STATE " + actualStateIntIndex);
}
}
}
}
这是输入文件：
4
3 2 1
ab
1 0
2 0
2 0
2
0 3
abaa
aab
aba
3 3 2
ade
0 1 2
1 2 0
2 1 0
1 2
2 2
a
de
3 2 1
ab
1 0
2 0
2 0
2
0 3
abaa
aab
aba
3 3 2
ade
0 1 2
1 2 0
2 1 0
1 2
2 2
a
de
编辑：在这里，我将解释此输入文件的格式
第一行代表测试案例的数量。
每个测试用例均以3个整数开头，第一个是自动机的状态数，第二个是字母中的符号数，然后是最终状态数。
下一行是字母。这些符号一起出现。
然后，有许多行等于描述过渡函数的状态数。这组线的第一行表示自动机（qo）中第一个状态的转换函数，第一个元素表示当字母表中的第一个符号进入该状态时所达到的状态，依此类推。我从原始的问题陈述中很难理解这一点。这是我来看的最简单的方法：
这些行：
1 0
2 0
2 0
等于：
AlphabetSymbol0 AlphabetSymbol1
State0 State1 State0
State1 State2 State0
State2 State2 State0
然后有一行显示哪些是自动机的最终状态。
然后出现一行，指出哪个是初始状态以及将要输入多少个输入字符串。
然后输入字符串与行。
该程序的输出应为：
C
ase Number 1
alphabetLine is ab
for the state 0 transitionsLine is 1 0
THE STATE 0 REACHES THE STATE 1 WITH THE SYMBOL a
THE STATE 0 REACHES THE STATE 0 WITH THE SYMBOL b
for the state 1 transitionsLine is 2 0
THE STATE 1 REACHES THE STATE 2 WITH THE SYMBOL a
THE STATE 1 REACHES THE STATE 0 WITH THE SYMBOL b
for the state 2 transitionsLine is 2 0
THE STATE 2 REACHES THE STATE 2 WITH THE SYMBOL a
THE STATE 2 REACHES THE STATE 0 WITH THE SYMBOL b
finalStatesLine is 2
THE STATE 2 IS MARKED AS FINAL
THE INITIAL STATE ID IS 0
THE STATE 0 IS MARKED AS INITIAL
stringToProcess is abaa
THE FOUND INITIAL ONE IS 0
the actual state for baa is 0
the actual state for aa is 0
the actual state for a is 0
the actual state for is 0
**THE STRING abaa IS ACCEPTED AT STATE 2**
stringToProcess is aab
THE FOUND INITIAL ONE IS 0
the actual state for ab is 0
the actual state for b is 0
the actual state for is 0
**THE STRING aab IS REJECTED AT STATE 0**
stringToProcess is aba
THE FOUND INITIAL ONE IS 0
the actual state for ba is 0
the actual state for a is 0
the actual state for is 0
**THE STRING aba IS ACCEPTED AT STATE 1**
Case Number 2
alphabetLine is ade
for the state 0 transitionsLine is 0 1 2
THE STATE 0 REACHES THE STATE 0 WITH THE SYMBOL a
THE STATE 0 REACHES THE STATE 1 WITH THE SYMBOL d
THE STATE 0 REACHES THE STATE 2 WITH THE SYMBOL e
for the state 1 transitionsLine is 1 2 0
THE STATE 1 REACHES THE STATE 1 WITH THE SYMBOL a
THE STATE 1 REACHES THE STATE 2 WITH THE SYMBOL d
THE STATE 1 REACHES THE STATE 0 WITH THE SYMBOL e
for the state 2 transitionsLine is 2 1 0
THE STATE 2 REACHES THE STATE 2 WITH THE SYMBOL a
THE STATE 2 REACHES THE STATE 1 WITH THE SYMBOL d
THE STATE 2 REACHES THE STATE 0 WITH THE SYMBOL e
finalStatesLine is 1 2
THE STATE 1 IS MARKED AS FINAL
THE STATE 2 IS MARKED AS FINAL
THE INITIAL STATE ID IS 2
THE STATE 2 IS MARKED AS INITIAL
stringToProcess is a
THE FOUND INITIAL ONE IS 2
the actual state for is 0
**THE STRING a IS ACCEPTED AT STATE 2**
stringToProcess is de
THE FOUND INITIAL ONE IS 2
the actual state for e is 0
the actual state for is 0
**THE STRING de IS REJECTED AT STATE 0**
我弄错了所有用粗体写的行。
我越来越：
Case Number 1
THE STRING abaa IS ACCEPTED AT STATE 0
THE STRING aab IS ACCEPTED AT STATE 0
THE STRING aba IS ACCEPTED AT STATE 0
Case Number 2
THE STRING a IS ACCEPTED AT STATE 0
THE STRING de IS ACCEPTED AT STATE 0
我的自动机正在接受一切并陷入状态0，为什么？
最佳答案
我很确定问题是State需要重写.equals（Object）和.hashCode（）。我相信allStates是一个List<State>，必须重写该List上的get（State）等于。