我的代码没有给出错误,但是没有显示最小值和最大值。代码是:
Scanner input = new Scanner(System.in);
int array[] = new int[10];
System.out.println("Enter the numbers now.");
for (int i = 0; i < array.length; i++) {
int next = input.nextInt();
// sentineil that will stop loop when 999 is entered
if (next == 999) {
break;
}
array[i] = next;
// get biggest number
getMaxValue(array);
// get smallest number
getMinValue(array);
}
System.out.println("These are the numbers you have entered.");
printArray(array);
// getting the maximum value
public static int getMaxValue(int[] array) {
int maxValue = array[0];
for (int i = 1; i < array.length; i++) {
if (array[i] > maxValue) {
maxValue = array[i];
}
}
return maxValue;
}
// getting the miniumum value
public static int getMinValue(int[] array) {
int minValue = array[0];
for (int i = 1; i < array.length; i++) {
if (array[i] < minValue) {
minValue = array[i];
}
}
return minValue;
}
//this method prints the elements in an array......
//if this case is true, then that's enough to prove to you that the user input has //been stored in an array!!!!!!!
public static void printArray(int arr[]) {
int n = arr.length;
for (int i = 0; i < n; i++) {
System.out.print(arr[i] + " ");
}
}
我是否需要system.out.println()来显示它,否则返回应该起作用吗?
最佳答案
getMaxValue(array);
// get smallest number
getMinValue(array);
您正在调用方法,但不使用返回的值。
System.out.println(getMaxValue(array));
System.out.println(getMinValue(array));