我正在尝试使用PHPExcel从数据库中获取表的字段名。
但是,我有个错误说
mysql_field_name()要求参数2为长字符串,在
C:\xampp\htdocs\phpexcelsample\download.php,第42行
我想我在这里遗漏了一些东西。。。你能告诉我如何得到域名吗?
这是我的代码:
<?php
$dbhost= "localhost"; //your MySQL Server
$dbuser = "root"; //your MySQL User Name
$dbpass = ""; //your MySQL Password
$dbname = "sales";
//your MySQL Database Name of which database to use this
$tablename = "deposit";
//your MySQL Table Name which one you have to create excel file
// your mysql query here , we can edit this for your requirement
$sql = "Select * from $tablename ";
//create code for connecting to mysql
$connect = @mysql_connect($dbhost, $dbuser, $dbpass)
or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" .
mysql_errno());
//select database
$Db = @mysql_select_db($dbname, $connect)
or die("Couldn't select database:<br>" . mysql_error(). "<br>" .
mysql_errno());
//execute query
$result = @mysql_query($sql,$connect)
or die("Couldn't execute query:<br>" . mysql_error(). "<br>" .
mysql_errno());
error_reporting(E_ALL);
require_once 'Classes/PHPExcel.php';
// Execute the database query
// Instantiate a new PHPExcel object
$objPHPExcel = new PHPExcel();
// Set the active Excel worksheet to sheet 0
$objPHPExcel->setActiveSheetIndex(0);
// Initialise the Excel row number
$rowCount = 1;
//start of printing column names as names of MySQL fields
$column = 'A';
for ($i = 1; $i < mysql_num_fields($result); $i++)
{
//$objPHPExcel->getActiveSheet()->setCellValue($column.$rowCount,
mysql_field_name($result,$i));
$objPHPExcel->getActiveSheet()->setCellValue($column.$rowCount,
mysql_field_name($result,'EMPLOYEE'));
$column++;
}
//end of adding column names
//start while loop to get data
$rowCount = 2;
while($row = mysql_fetch_row($result))
{
$column = 'A';
for($j=1; $j<mysql_num_fields($result);$j++)
{
if(!isset($row[$j]))
$value = NULL;
elseif ($row[$j] != "")
$value = strip_tags($row[$j]);
else
$value = "";
$objPHPExcel->getActiveSheet()->setCellValue($column.$rowCount, $value);
$column++;
}
$rowCount++;
}
// Redirect output to a client’s web browser (Excel5)
header('Content-Type: application/vnd.ms-excel');
header('Content-Disposition: attachment;filename="Result.xls"');
header('Cache-Control: max-age=0');
$objWriter = PHPExcel_IOFactory::createWriter($objPHPExcel, 'Excel5');
$objWriter->save('php://output');
?>
最佳答案
你的错记在这里,因为mysql字段名在第二个参数http://php.net/manual/en/function.mysql-field-name.php中需要整数
如果要显示特定的字段名,则可以将其放入数组并使用它。例如:
<?php
$query = 'SHOW COLUMNS FROM `table`';
$fields = [];
try {
/* $mysqli connection object */
if(!$res = $mysqli->query($query)) {
throw new Exception($mysqli->error);
}
while($row = $res->fetch_assoc()) {
$fields[] = $row['Field'];
}
} catch(Exception $e) {
echo $e->getMessage();
}
var_dump($fields);
看看http://php.net/manual/en/book.mysqli.php
关于php - 使用PHPExcel从MySQL到Excel获取字段名称,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/45031013/