我在Python中使用openCV查找一张纸的角以使其变形。
img = cv2.imread(images[i])
corners = cv2.goodFeaturesToTrack(cv2.cvtColor(img,cv2.COLOR_BGR2GRAY),4,.01,1000,useHarrisDetector=True,k=.04)
corners = np.float32(corners)
print(corners)
ratio = 1.6
cardH = math.sqrt((corners[2][0][0] - corners[1][0][0]) * (corners[2][0][0] - corners[1][0][0]) + (corners[2][0][1] - corners[1][0][1]) * (
corners[2][0][1] - corners[1][0][1]))
cardW = ratio * cardH;
pts2 = np.float32(
[[corners[0][0][0], corners[0][0][1]], [corners[0][0][0] + cardW, corners[0][0][1]], [corners[0][0][0] + cardW, corners[0][0][1] + cardH],
[corners[0][0][0], corners[0][0][1] + cardH]])
M = cv2.getPerspectiveTransform(corners, pts2)
offsetSize = 500
transformed = np.zeros((int(cardW + offsetSize), int(cardH + offsetSize)), dtype=np.uint8);
dst = cv2.warpPerspective(img, M, transformed.shape)
之前:
https://imgur.com/a/H7HjFro
后:
https://imgur.com/a/OA6Iscq
从这些图像可以看到，它们检测的是纸张本身内部的边缘，而不是纸张的角落。我应该考虑完全使用其他算法吗？我很迷茫。
我尝试将最小欧几里德距离增加到1000，但这确实没有任何作用。
请注意，这不是真实的信息，这是在Kaggle上发现的虚假数据集。
kaggle数据集可以找到https://www.kaggle.com/mcvishnu1/fake-w2-us-tax-form-dataset
最佳答案
这是在Python / OpenCV中执行此操作的一种方法。
请注意，找到的角是从最高角开始逆时针列出的。
输入:
import cv2
import numpy as np
# read image
img = cv2.imread("efile.jpg")
# convert img to grayscale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# blur image
blur = cv2.GaussianBlur(gray, (3,3), 0)
# do otsu threshold on gray image
thresh = cv2.threshold(blur, 0, 255, cv2.THRESH_BINARY+cv2.THRESH_OTSU)[1]
# apply morphology
kernel = np.ones((7,7), np.uint8)
morph = cv2.morphologyEx(thresh, cv2.MORPH_CLOSE, kernel)
morph = cv2.morphologyEx(morph, cv2.MORPH_OPEN, kernel)
# get largest contour
contours = cv2.findContours(morph, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
contours = contours[0] if len(contours) == 2 else contours[1]
area_thresh = 0
for c in contours:
area = cv2.contourArea(c)
if area > area_thresh:
area_thresh = area
big_contour = c
# draw white filled largest contour on black just as a check to see it got the correct region
page = np.zeros_like(img)
cv2.drawContours(page, [big_contour], 0, (255,255,255), -1)
# get perimeter and approximate a polygon
peri = cv2.arcLength(big_contour, True)
corners = cv2.approxPolyDP(big_contour, 0.04 * peri, True)
# draw polygon on input image from detected corners
polygon = img.copy()
cv2.polylines(polygon, [corners], True, (0,0,255), 1, cv2.LINE_AA)
# Alternate: cv2.drawContours(page,[corners],0,(0,0,255),1)
# print the number of found corners and the corner coordinates
# They seem to be listed counter-clockwise from the top most corner
print(len(corners))
print(corners)
# for simplicity get average of top/bottom side widths and average of left/right side heights
# note: probably better to get average of horizontal lengths and of vertical lengths
width = 0.5*( (corners[0][0][0] - corners[1][0][0]) + (corners[3][0][0] - corners[2][0][0]) )
height = 0.5*( (corners[2][0][1] - corners[1][0][1]) + (corners[3][0][1] - corners[0][0][1]) )
width = np.int0(width)
height = np.int0(height)
# reformat input corners to x,y list
icorners = []
for corner in corners:
pt = [ corner[0][0],corner[0][1] ]
icorners.append(pt)
icorners = np.float32(icorners)
# get corresponding output corners from width and height
ocorners = [ [width,0], [0,0], [0,height], [width,height] ]
ocorners = np.float32(ocorners)
# get perspective tranformation matrix
M = cv2.getPerspectiveTransform(icorners, ocorners)
# do perspective
warped = cv2.warpPerspective(img, M, (width, height))
# write results
cv2.imwrite("efile_thresh.jpg", thresh)
cv2.imwrite("efile_morph.jpg", morph)
cv2.imwrite("efile_polygon.jpg", polygon)
cv2.imwrite("efile_warped.jpg", warped)
# display it
cv2.imshow("efile_thresh", thresh)
cv2.imshow("efile_morph", morph)
cv2.imshow("efile_page", page)
cv2.imshow("efile_polygon", polygon)
cv2.imshow("efile_warped", warped)
cv2.waitKey(0)
阈值图片:
形态清除图像:
在输入上绘制的多边形:
提取的角(从右上角逆时针方向)
4
[[[693 67]]
[[ 23 85]]
[[ 62 924]]
[[698 918]]]
扭曲的结果:
关于python-3.x - 当纸张本身上有打印的角/线时，如何找到纸张的角？，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/60941012/