我正在使用apache POI 3.7。我正在尝试替换Word文档(docx)中表列的值。但是,我所做的是它一直在文档中附加当前值的值。但是,如果表列的值为空,则会放置该值。您能给我一些解决方法的想法吗?以下是我到目前为止完成的代码。
提前致谢。
package test.doc;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.List;
import org.apache.poi.xwpf.usermodel.XWPFDocument;
import org.apache.poi.xwpf.usermodel.XWPFParagraph;
import org.apache.poi.xwpf.usermodel.XWPFTable;
import org.apache.poi.xwpf.usermodel.XWPFTableCell;
import org.apache.poi.xwpf.usermodel.XWPFTableRow;
public class POIDocXTableTest {
public static void main(String[] args)throws IOException {
String fileName = "C:\\Test.docx";
InputStream fis = new FileInputStream(fileName);
XWPFDocument document = new XWPFDocument(fis);
List<XWPFParagraph> paragraphs = document.getParagraphs();
for (int x=0; x<paragraphs.size();x++)
{
XWPFParagraph paragraph = paragraphs.get(x);
System.out.println(paragraph.getParagraphText());
}
List<XWPFTable> tables = document.getTables();
for (int x=0; x<tables.size();x++)
{
XWPFTable table = tables.get(x);
List<XWPFTableRow> tableRows = table.getRows();
tableRows.remove(x);
for (int r=0; r<tableRows.size();r++)
{
System.out.println("Row "+ (r+1)+ ":");
XWPFTableRow tableRow = tableRows.get(r);
List<XWPFTableCell> tableCells = tableRow.getTableCells();
for (int c=0; c<tableCells.size();c++)
{
System.out.print("Column "+ (c+1)+ ": ");
XWPFTableCell tableCell = tableCells.get(c);
//tableCell.setText("TAE");
String tableCellVal = tableCell.getText();
if ((c+1)==2){
if (tableCellVal!=null){
if (tableCellVal.length()>0){
char c1 = tableCellVal.charAt(0);
String s2 = "-TEST";
char c2 = s2.charAt(0);
String test = tableCell.getText().replace(tableCellVal,s2);
tableCell.setText(test);
}else{
//tableCell.setText("NULL");
}
}
}
System.out.println("tableCell.getText(" + (c) + "):" + tableCellVal);
}
}
System.out.println("\n");
}
OutputStream out = new FileOutputStream(fileName);
document.write(out);
out.close();
}
}
最佳答案
防止段落中的样式并查找具有不同样式的搜索字符串的最佳解决方案是以下方法:
private long replaceInParagraphs(Map<String, String> replacements, List<XWPFParagraph> xwpfParagraphs) {
long count = 0;
for (XWPFParagraph paragraph : xwpfParagraphs) {
List<XWPFRun> runs = paragraph.getRuns();
for (Map.Entry<String, String> replPair : replacements.entrySet()) {
String find = replPair.getKey();
String repl = replPair.getValue();
TextSegement found = paragraph.searchText(find, new PositionInParagraph());
if ( found != null ) {
count++;
if ( found.getBeginRun() == found.getEndRun() ) {
// whole search string is in one Run
XWPFRun run = runs.get(found.getBeginRun());
String runText = run.getText(run.getTextPosition());
String replaced = runText.replace(find, repl);
run.setText(replaced, 0);
} else {
// The search string spans over more than one Run
// Put the Strings together
StringBuilder b = new StringBuilder();
for (int runPos = found.getBeginRun(); runPos <= found.getEndRun(); runPos++) {
XWPFRun run = runs.get(runPos);
b.append(run.getText(run.getTextPosition()));
}
String connectedRuns = b.toString();
String replaced = connectedRuns.replace(find, repl);
// The first Run receives the replaced String of all connected Runs
XWPFRun partOne = runs.get(found.getBeginRun());
partOne.setText(replaced, 0);
// Removing the text in the other Runs.
for (int runPos = found.getBeginRun()+1; runPos <= found.getEndRun(); runPos++) {
XWPFRun partNext = runs.get(runPos);
partNext.setText("", 0);
}
}
}
}
}
return count;
}
此方法适用于跨越多个Run的搜索字符串。替换的零件从第一个找到的Run中获取样式。