来自集合的示例文档

{
    "_id" : 2,
    "student" : "Ryan",
    "homework" : [
        5,
        6,
        5
    ],
    "quiz" : [
        8,
        8
    ],
    "extraCredit" : 8
}

MongoDB中的聚合查询
db.scores.aggregate([
     {
        $project : {
            _id:"$_id",
            hSum : { $sum: "$homework" },
            qSum : { $sum: "$quiz"},
        }
     }])

上述聚合查询的输出
{
    "_id" : 2,
    "hSum" : 16,
    "qSum" : 16
}

我想把上面的mongo查询转换成spring数据格式。
我想用spring数据中的projectionoperations进行聚合。如何使用projectionoperation编写?

最佳答案

这应该管用

MatchOperation matchOperation = match(Criteria.where("_id").is(2));

AggregationExpression homeworkExpression = AccumulatorOperators.Sum.sumOf("homework");
AggregationExpression quizExpression = AccumulatorOperators.Sum.sumOf("quiz");
ProjectionOperation projectionOperation = project("someId").and(homeworkExpression).as("hSum")
        .and(quizExpression).as("qSum");

Aggregation aggregation = newAggregation( matchOperation, projectionOperation);
AggregationResults<Result> results = mongoTemplate.aggregate(aggregation, "ScoresColletionName", Result.class);

您可以创建一个名为result的类来获取
@Getter
@Setter
class Result {
    private int someId;
    private int hSum;
    private int qSum;
}

07-24 16:34