我正在创建一个预订系统,它有两张桌子
房间
id | name | no_of_rooms
1 | Lake View | 4
2 | Royale | 2
3 | Sky View | 6
预订
id |room_id | start | end | total_rooms
4 |1 | 2015-08-13 | 2015-08-14 | 2
5 |2 | 2015-08-20 | 2015-08-22 | 1
6 |2 | 2015-08-01 | 2015-08-13 | 1
在搜索页面上创建新预订时,我希望找到在此日期范围内可用的房间
搜索值
开始时间:2015-08-11
结束日期:2015-08-12
预期结果
id | name | no_of_rooms | available_rooms
1 | Lake View | 4 | 4
2 | Royale | 2 | 1
3 | Sky View | 6 | 6
我得到的结果
id | name | no_of_rooms | available_rooms
1 | Lake View | 4 | 0
2 | Royale | 2 | 1
3 | Skyview | 6 | 0
这是我写的房间可用性代码
SELECT
r.id,
r.name,
r.no_of_rooms,
IFNULL(sum(b.total_rooms),0) as available_rooms
FROM rooms r
LEFT JOIN bookings b ON r.id = b.room_id AND
(
(b.start <= "2015-08-11" AND b.end >= "2015-08-11")
OR
(b.start <= "2015-08-12" AND b.end >= "2015-08-12")
)
GROUP BY r.id
我也不想让显示不可用的房间。无论我尝试了什么结果都是完全错误的。希望你们能帮助我!
最佳答案
您可以尝试:
SELECT r.id AS roomID, r.name, r.no_of_rooms,
r.no_of_rooms - COALESCE(t.bookedRooms,0) AS available_rooms
FROM rooms AS r
LEFT JOIN (
SELECT room_id, SUM(total_rooms) AS bookedRooms
FROM bookings
WHERE `start` < '2015-08-14' AND `end` > '2015-08-11'
GROUP BY room_id ) AS t
ON r.id = t.room_id
WHERE r.no_of_rooms - COALESCE(t.bookedRooms,0) > 0
查找指定期间的预订房间的关键是以下谓词:
`start` <= '2015-08-12' AND `end` >= '2015-08-11'
以上是预订周期与指定周期重叠的所有房间,即使是一天。
使用
GROUP BY
onroom_id
可以得到指定期间每个room_id
的预订房间总数。为了得到预期的结果集,我们可以用预订总量的派生表做一个
LEFT JOIN
,然后简单地从可用房间的数量中减去预订房间的总和。Demo here
关于mysql - mysql查询以获取日期范围未给出预期结果之间所有未预订的房间,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32142460/