bash - bash将换行符替换为引号

我有以下CSV文件：

"test","test2","test
3 and some other

data"
"test4","test5","test6 and some other


data"

我想用字符\n替换所有换行符（windows或unix样式），这样我将获得：

"test","test2","test\n3 and some other\n\ndata"
"test4","test5","test6 and some other\n\n\ndata"

我尝试过awk但没有成功：

cat myFile.csv | awk -F \" -v OFS=\" '{
   for (i=0; i<NF; i++) {
      gsub("\\n", "\\\\n", $i)
   }
   print
}'

最佳答案

有一种方法：

$ awk '!/"$/{sub(/$/,"\\n");printf "%s",$0;next}1' file
"test","test2","test\n3 and some other\n\ndata"
"test4","test5","test6 and some other\n\n\ndata"

关于bash - bash将换行符替换为引号，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/16036744/