c# - 从托管C++到C#的结构列表

首先，我想提及这个问题：Sharing variables between C# and C++。
这似乎是我要找的，但当我试图实现这一点时，我得到了一些错误。
首先这是我的代码：
C++

namespace CppWrapping
{
    #pragma pack(1)
    public struct MyPoint
    {
    public:
        float X;
        float Y;
        float Z;
        unsigned char R;
        unsigned char G;
        unsigned char B;
        unsigned char A;

    }MyPoint_t;
    #pragma pack()

    public ref class MyCppWrapper
    {
    public:
        MyCpplWrapper(void);
        List<MyPoint>^ getData();
    };
};

C++MyCPPrPAPP.CPP

List<MyPoint>^ MyCppWrapper::getData()
{
    List<MyPoint>^ temp = gcnew List<MyPoint>();
    for (int i = 0; i < Data.Length; i++)
    {
        PointT& pt = Data.points[i];
        MyPoint holder = MyPoint();
        holder.X = pt.x;
        holder.Y = pt.y;
        holder.Z = pt.z;
        holder.R = pt.r;
        holder.G = pt.g;
        holder.B = pt.b;
        holder.A = pt.a;
        temp[i] = holder;
    }
    return temp;
}

c mylinker.cs公司

[StructLayout(LayoutKind.Sequential, Pack = 1)]
private struct MyPoint_t
{
    public float X;
    public float Y;
    public float Z;
    public byte R;
    public byte G;
    public byte B;
    public byte A;
};

public void getData()
{
    _wrapper = new MyCppWrapper();
    List<MyPoint_t> data = _wrapper.getData();
}

有很多错误，但归根结底是这三个错误：

error C3225: generic type argument for 'T' cannot be 'CppWrapping::MyPoint', it must be a value type or a handle to a reference type

'CppWrapping.MyPoint' is inaccessible due to its protection level

'CppWrapping.MyCppWrapper.getData()' is inaccessible due to its protection level

当我将光标悬停在代码List data = _wrapper.getData();下时，也会得到一个红色标记：

Cannot convert source type 'System.Collections.Generic.List<CppWrapping.MyPoint>' to target type 'System.Collections.Generic.List<ProjectA.MyLinker.MyPoint_t>'

我该怎么解决？
编辑：
我把public struct MyPoint改成public value struct MyPoint
将错误数量从58减少到1。
我现在犯的错误是：

Cannot implicitly convert type 'System.Collections.Generic.List<CppWrapping.MyPoint>' to 'System.Collections.Generic.List<ProjectA.MyLinker.MyPoint_t>'

最佳答案

public struct MyPoint {}

这声明了一个非托管结构，您的c代码无法访问它，因为它被导出为没有任何成员的不透明值类型。你必须声明

public value struct MyPoint {}

接下来要做的是从C代码中删除MyPoint声明。类型标识包括该类型来自的程序集，因此mypoint\u t与mypoint不兼容。您可以简单地使用C++/CLI程序集中的MyPoT类型：

_wrapper = new MyCppWrapper();
List<MyPoint> data = _wrapper.getData();

或者利用c中的类型推断：

var data = _wrapper.getData();