由于业务需要,要求实现树形菜单,且菜单数据由后台返回,在网上找了几篇文章,看下来总算有了解决办法。

场景:根据业务要求,需要实现活动的树形菜单,菜单数据由后台返回,最后的效果图如下:

后台返回的数据格式是这个样子的:

data=[{
 pID:'1',//父ID
 name:'目录一',
menuID:'m1',//本身ID
              isContent:false//判断是否是目录
},
 {
pID:'1',
 name:'目录二',
menuID:'m2',
              isContent:false
 },
 {
 pID:'m1',
 name:'目录一--菜单一',
menuID:'m11',
              isContent:true
 },
 {
 pID:'m1',
 name:'目录一--目录一',
menuID:'m12',
              isContent:false
 },
           {
            pID:'m12',
 name:'目录一--目录一--菜单一',
menuID:'m121',
             isContent:true
 },
 {
 pID:'m2',
 name:'目录二--菜单一',
menuID:'m21',
              isContent:true
 },
 {
 pID:'m2',
 name:'目录二--菜单二',
menuID:'m22',
              isContent:true
 },
 ]

这是一串具有父子关系的数据,首先就是要把这一大串数据转化成树形结构:

tree(){
        let data=[{
              pID:'1',//父ID
              name:'目录一',
              menuID:'m1',//本身ID
                isContent:false//判断是否是目录
            },
            {
              pID:'1',
              name:'目录二',
              menuID:'m2',
                isContent:false
            },
            {
              pID:'m1',
              name:'目录一--菜单一',
              menuID:'m11',
                isContent:true
            },
            {
              pID:'m1',
              name:'目录一--目录一',
              menuID:'m12',
                isContent:false
            },
             {
                pID:'m12',
              name:'目录一--目录一--菜单一',
              menuID:'m121',
               isContent:true
            },
            {
              pID:'m2',
              name:'目录二--菜单一',
              menuID:'m21',
                isContent:true
            },
            {
              pID:'m2',
              name:'目录二--菜单二',
              menuID:'m22',
                isContent:true
            },
          ]
        let tree = []
        for(let i=0;i<data.length;i++){
          if(data[i].pID == '1'){
            let obj = data[i]
            obj.list = []
            tree.push(obj)
            data.splice(i,1)
            i--
          }
        }
        menuList(tree)
        console.log(tree)
        function menuList(arr){
          if(data.length !=0){
            for(let i=0; i<arr.length;i++){
              for(let j=0;j<data.length;j++){
                if(data[j].pID == arr[i].menuID){
                  let obj = data[j]
                  obj.list = []
                  arr[i].list.push(obj)
                  data.splice(j,1)
                  j--
                }
              }
              menuList(arr[i].list)
            }
          }
        }
      }

运行完后返回的结构就是这个样子:

[{"pID":"1","name":"目录一","menuID":"m1","isContent":false,"list":[{"pID":"m1","name":"目录一--菜单一","menuID":"m11","isContent":true,"list":[]},{"pID":"m1","name":"目录一--目录一","menuID":"m12","isContent":false,"list":[{"pID":"m12","name":"目录一--目录一--菜单一","menuID":"m121","isContent":true,"list":[]}]}]},{"pID":"1","name":"目录二","menuID":"m2","isContent":false,"list":[{"pID":"m2","name":"目录二--菜单一","menuID":"m21","isContent":true,"list":[]},{"pID":"m2","name":"目录二--菜单二","menuID":"m22","isContent":true,"list":[]}]}]

接下来就要展示了,项目中用的element-ui的导航菜单组件,为了实现这样的树形结构,将每一级的菜单单独作为一个组件,通过判断isContent的值来递归。我直接把代码贴出来

<el-menu
      theme="dark"
      :default-active="openMenuID"
      :default-openeds="openMenuArr"
      class="el-menu"
     @select="handleSelect">
      <template v-for="(item,index) in menuList">
         <el-submenu :index=item.menuID v-if="item.IsContent">
           <template slot="title">
          <i class="el-icon-menu"></i>
             {{item.name}}
           </template>
           <tree-menu :data="item.list"></tree-menu>
         </el-submenu>
         <el-menu-item :index=item.menuID v-else>{{item.name}}</el-menu-item>
      </template>
    </el-menu>

tree-menu组件的代码:

<template v-for="(menu,index) in data">
      <el-submenu :index=menu.menuID v-if="menu.IsContent">
        <template slot="title">
          <i class="el-icon-plus"></i>
          {{menu.name}}</template>
        <tree-menu :data="menu.list"></tree-menu>
      </el-submenu>
      <el-menu-item v-else :index=menu.menuID>
        {{menu.name}}
      </el-menu-item>
    </template>

总结

以上所述是小编给大家介绍的vue.js与element-ui实现菜单树形结构的解决方法,希望对大家有所帮助,如果大家有任何疑问欢迎给我留言,小编会及时回复大家的!

02-07 11:28