我被困在ILSurface中绘制表面。
该方案如下:
绘制不规则网格:
float[] x = new float[sizeX]; // filled with timestamps
float[] y = new float[sizeY]; // filled with values
float[,] z = new float[sizeX, sizeY]; // filled with values mapped by [x,y]
ILInArray<float> inX = ILMath.array(x);
ILInArray<float> inY = ILMath.array(y);
ILInArray<float> inZ = ILMath.meshgrid(inX * inY, inX, inY);
// how do i fill the inZ with z[,]?
ILRetArray<float> outMesh = ILMath.meshgrid(inX, inY, inZ, null, null);
plotCube.Add(new ILSurface(outMesh, null, null, null, null));
// plotCube already attached to the scene, and the scene with the ILPanel
ilPanel1.Refresh();
想要将此映射到数组中,以便可以将其绘制在
ILSurface
上。我尝试了一些
ILMath.meshgrid
来填充ILInArray<double> ZXYArray
并没有成功。希望我已经清楚了。任何帮助欢迎。
谢谢。
最佳答案
这是一个简单的示例,该示例如何使用ILNumerics绘制3D曲面并提供自定义X和Y范围。它期望使用ILNumerics常规安装Windows.Forms应用程序:
private void ilPanel1_Load(object sender, EventArgs e) {
// define X and Y range
ILArray<float> X = ILMath.vec<float>(-10.0, 0.1, 10.0);
ILArray<float> Y = ILMath.vec<float>(-6.0, 0.1, 6.0);
// compute X and Y coordinates for every grid point
ILArray<float> YMat = 1; // provide YMat as output to meshgrid
ILArray<float> XMat = ILMath.meshgrid(X, Y, YMat); // only need mesh for 2D function here
// preallocate data array for ILSurface: X by Y by 3
// Note the order: 3 matrix slices of X by Y each, for Z,X,Y coordinates of every grid point
ILArray<float> A = ILMath.zeros<float>(Y.Length, X.Length, 3);
// fill in Z values (replace this with your own function / data!!)
A[":;:;0"] = ILMath.sin(XMat) * ILMath.sin(YMat) * ILMath.exp(-ILMath.abs(XMat * YMat) / 5);
A[":;:;1"] = XMat; // X coordinates for every grid point
A[":;:;2"] = YMat; // Y coordinates for every grid point
// setup the scene + plot cube + surface
ilPanel1.Scene = new ILScene() {
new ILPlotCube(twoDMode: false) {
new ILSurface(A) {
UseLighting = true,
Children = { new ILColorbar() }
}
}
};
}
它产生以下结果:
这是相同的示例as interactive Web Component。
注意定义网格点坐标的顺序。请参阅此处的文档:http://ilnumerics.net/surface-plots.html