Reverse a linked list from position m to n. Do it in one-pass.
Note: 1 ≤ m ≤ n ≤ length of list.
Example:
Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ class Solution { public ListNode reverseBetween(ListNode head, int m, int n) { ListNode dummy = new ListNode(-1); dummy.next = head; ListNode cur1 = dummy; ListNode pre1 = null; for (int i = 0; i < m; i++) { pre1 = cur1; cur1 = cur1.next; } ListNode cur2 = cur1; ListNode pre2 = pre1; ListNode nxt = null; for(int i = m; i <= n; i++) { nxt = cur2.next; cur2.next = pre2; pre2 = cur2; cur2 = nxt; } // connect 1 -> 4 pre1.next = pre2; // connnect 2 -> 5 cur1.next = cur2; return dummy.next; } }